Consider the CMOS circuit shown in the figure (substrates are connect...
Given
(i) Both transistors have same gate oxide capacitance
(ii) VThp = -1 V
(iii) VThN = 1 V
For n MOSFET :
Condition for saturation is given by,
If this inequality is satisfied then n MOSFET will be operate in saturation region.
From given circuit,
Therefore n MOSFET is operated in saturation region.
For p MOSFET :
Condition for saturation is given by
If this inequality is satisfied then p MOSFET will be operate in saturation region.
From given circuit,
Therefore p MOSFET is operated in saturation region.
We can say that, whenever gate and drain terminal of n MOSFET and p MOSFET connected together, both MOSFET will be operated in saturation region.
Since, current flow through gate terminal of MOSFETs is zero, hence both MOSFET will have same drain current.
300(V0 - 1)2 = 40 x 5(4 - V0 - 1)2
3(V0 - 1)2 = 2(3 - V0)2
3V20 + 3 - 6V0 = 18 + 2V20 - 12V0
V20 + 6V0 - 15 = 0
V0 = 1.89V,- 7.89 V
Taking negative value of V0 .
V0 = -7.89 V
For n MOSFET :
Hence, n MOSFET will be OFF and drain current IDN = 0
Since, drain current through n MOSFET is zero so we do not need to check whether p MOSFET is ON or OFF.
Taking positive value of V0 .
V0 = 1.89 V
For n MOSFET :
Hence, n MOSFET will be ON for V0 = 1.89 V
Now we will check n MOSFET is operate either in saturation or linear region
The condition for saturation is given by,
1.89V ≥ 1.89 - 1V
1.89 ≥ 0.89
Therefore, n MOSFET is operates in saturation region for V0 = 1.89 V
For p MOSFET :
Hence, p MOSFET will be ON for V0 = 1.89 V
Now we will check p MOSFET is operate either in saturation or in linear region. V0 = 1.89 V
The conditions for saturation is given by,
2.11V ≥ 2.11V - 1V
2.11 ≥ 1.11
Therefore, p MOSFET is operates in saturation region for V0 = 1.89 V .
Hence, the correct option is (D).