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An E. coli cell with a mutated lac-z gene, due to which it is unable to synthesise the corresponding enzyme, is still growing in the nutrient medium. It indicates that medium is supplemented with energy source/enzyme
  • a)
    β-galactoside
  • b)
    Glucose
  • c)
    β-galactosidase
  • d)
    Lactose
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An E. coli cell with a mutated lac-z gene, due to which it is unable ...
Lac - z gene is responsible for synthesis of β-galactosidase that breaks lactose into galactose and glucose. If the growing medium has glucose then, there is no need of β-galactosidase.
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Community Answer
An E. coli cell with a mutated lac-z gene, due to which it is unable ...
Explanation:

Glucose as an energy source:
- E. coli can utilize glucose as an energy source through glycolysis, a process that does not involve the lac-z gene or the β-galactosidase enzyme.
- Even if the lac-z gene is mutated and the enzyme is not synthesized, the E. coli cell can still grow and survive on the glucose present in the nutrient medium.
- Glucose is a primary energy source for many organisms, including E. coli, and can support cell growth and metabolism even in the absence of lactose or β-galactosidase activity.
Therefore, the presence of glucose in the medium allows the E. coli cell with a mutated lac-z gene to continue growing despite the inability to synthesize the corresponding enzyme.
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An E. coli cell with a mutated lac-z gene, due to which it is unable to synthesise the corresponding enzyme, is still growing in the nutrient medium. It indicates that medium is supplemented with energy source/enzymea)β-galactosideb)Glucosec)β-galactosidased)LactoseCorrect answer is option 'B'. Can you explain this answer?
Question Description
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