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A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)?
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A solution containing 0.139g CrCl3.6H2O was passed through a cation ex...
Solution Analysis
The given solution contains 0.139g CrCl3.6H2O. The molar mass of CrCl3.6H2O is 266.5 g/mol. Therefore, the moles of CrCl3.6H2O present in the solution can be calculated as follows:
Moles = Mass/Molar mass
Moles = 0.139g/266.5 g/mol
Moles = 0.00052 mol
The acid coming out of the cation exchange resin required 28.5 ml of NaOH. The concentration of NaOH can be assumed to be 0.1 M. Therefore, the moles of NaOH required can be calculated as follows:
Moles of NaOH = Concentration x Volume
Moles of NaOH = 0.1 M x 0.0285 L
Moles of NaOH = 0.00285 mol
Determination of Correct Formula of Complex
The acid that comes out of the cation exchange resin is the result of the reaction between Cr3+ ions and H+ ions. The balanced chemical equation for this reaction can be written as follows:
Cr3+ + 3H+ → Cr(H2O)63+
Therefore, the number of moles of Cr3+ ions present in the solution can be calculated as follows:
Moles of Cr3+ = Moles of H+ = 0.00285 mol
The complex ion Cr(H2O)63+ has a molar mass of 266.5 g/mol. Therefore, the mass of the complex ion present in the solution can be calculated as follows:
Mass of complex ion = Moles x Molar mass
Mass of complex ion = 0.00285 mol x 266.5 g/mol
Mass of complex ion = 0.757 g
The mass of CrCl3.6H2O present in the solution was 0.139g. Therefore, the mass of the complex ion that was formed can be calculated as follows:
Mass of complex ion formed = Total mass – Mass of CrCl3.6H2O
Mass of complex ion formed = 0.757 g – 0.139 g
Mass of complex ion formed = 0.618 g
Therefore, the number of moles of the complex ion formed can be calculated as follows:
Moles of complex ion formed = Mass/Molar mass
Moles of complex ion formed = 0.618 g/266.5 g/mol
Moles of complex ion formed = 0.00232 mol
The formula of the complex ion can be determined by comparing the number of moles of Cr3+ ions and the number of moles of the complex ion formed. The ratio of moles of Cr3+ ions to moles of the complex ion formed is 1:1. Therefore, the correct formula of the complex ion is Cr(H2O)63+.
The given solution contains 0.139g CrCl3.6H2O. The molar mass of CrCl3.6H2O is 266.5 g/mol. Therefore, the moles of CrCl3.6H2O present in the solution can be calculated as follows:
Moles = Mass/Molar mass
Moles = 0.139g/266.5 g/mol
Moles = 0.00052 mol
The acid coming out of the cation exchange resin required 28.5 ml of NaOH. The concentration of NaOH can be assumed to be 0.1 M. Therefore, the moles of NaOH required can be calculated as follows:
Moles of NaOH = Concentration x Volume
Moles of NaOH = 0.1 M x 0.0285 L
Moles of NaOH = 0.00285 mol
Determination of Correct Formula of Complex
The acid that comes out of the cation exchange resin is the result of the reaction between Cr3+ ions and H+ ions. The balanced chemical equation for this reaction can be written as follows:
Cr3+ + 3H+ → Cr(H2O)63+
Therefore, the number of moles of Cr3+ ions present in the solution can be calculated as follows:
Moles of Cr3+ = Moles of H+ = 0.00285 mol
The complex ion Cr(H2O)63+ has a molar mass of 266.5 g/mol. Therefore, the mass of the complex ion present in the solution can be calculated as follows:
Mass of complex ion = Moles x Molar mass
Mass of complex ion = 0.00285 mol x 266.5 g/mol
Mass of complex ion = 0.757 g
The mass of CrCl3.6H2O present in the solution was 0.139g. Therefore, the mass of the complex ion that was formed can be calculated as follows:
Mass of complex ion formed = Total mass – Mass of CrCl3.6H2O
Mass of complex ion formed = 0.757 g – 0.139 g
Mass of complex ion formed = 0.618 g
Therefore, the number of moles of the complex ion formed can be calculated as follows:
Moles of complex ion formed = Mass/Molar mass
Moles of complex ion formed = 0.618 g/266.5 g/mol
Moles of complex ion formed = 0.00232 mol
The formula of the complex ion can be determined by comparing the number of moles of Cr3+ ions and the number of moles of the complex ion formed. The ratio of moles of Cr3+ ions to moles of the complex ion formed is 1:1. Therefore, the correct formula of the complex ion is Cr(H2O)63+.
Community Answer
A solution containing 0.139g CrCl3.6H2O was passed through a cation ex...
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A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)?
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A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)?.
A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 0.139g CrCl3.6H2O was passed through a cation exchange resin and acid coming out of the cation exchange resin required 28.5 ml of NaOH . Determine correct formula of the complex ( mol wt of complex 266.5)?.
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