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Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygous
normal woman. What proportion of the children would be expected to develop the hemolytic disease ?
normal woman. What proportion of the children would be expected to develop the hemolytic disease ?
- a)1/5
- b)1/10
- c)1/15
- d)1/20
Correct answer is option 'D'. Can you explain this answer?
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Hemolytic juandice is caused due to a dominant gene but only 10 percen...
Introduction:
Hemolytic jaundice is a genetic disorder characterized by the breakdown of red blood cells, leading to the accumulation of bilirubin in the blood. It is caused by a dominant gene, and only 10 percent of individuals with the gene develop the disease. In this scenario, a heterozygous man (carrying one copy of the gene) marries a homozygous normal woman (not carrying the gene).
Explanation:
To determine the proportion of children expected to develop the hemolytic disease, we need to consider the genetic inheritance pattern and the probability of passing on the gene.
Genetic Inheritance Pattern:
The gene responsible for hemolytic jaundice is dominant, meaning that a single copy of the gene is sufficient to cause the disease. When a heterozygous individual (Hh) mates with a homozygous normal individual (hh), the possible genotypes and phenotypes of their offspring can be predicted using a Punnett square.
The Punnett square for this cross would look like this:
| H | h |
-----------------
h | Hh | hh |
-----------------
h | Hh | hh |
Probability of Passing on the Gene:
In this case, the man is heterozygous (Hh) and the woman is homozygous normal (hh).
- Hh represents the genotype of the man, meaning that there is a 50% chance of passing on the dominant gene (H) to each offspring.
- The woman's genotype is hh, indicating that she does not carry the dominant gene and cannot pass it on to her offspring.
Expected Proportion of Children with Hemolytic Jaundice:
Based on the Punnett square and the probability of passing on the gene, the expected genotypes of the offspring would be:
- 50% chance of being Hh (heterozygous carriers)
- 50% chance of being hh (homozygous normals)
Since only individuals with the Hh genotype are carriers of the hemolytic jaundice gene, the proportion of children expected to develop the disease would be 50% of the total offspring.
Therefore, the correct answer is option 'D', which states that 1/20 (or 5%) of the children would be expected to develop the hemolytic disease.
Hemolytic jaundice is a genetic disorder characterized by the breakdown of red blood cells, leading to the accumulation of bilirubin in the blood. It is caused by a dominant gene, and only 10 percent of individuals with the gene develop the disease. In this scenario, a heterozygous man (carrying one copy of the gene) marries a homozygous normal woman (not carrying the gene).
Explanation:
To determine the proportion of children expected to develop the hemolytic disease, we need to consider the genetic inheritance pattern and the probability of passing on the gene.
Genetic Inheritance Pattern:
The gene responsible for hemolytic jaundice is dominant, meaning that a single copy of the gene is sufficient to cause the disease. When a heterozygous individual (Hh) mates with a homozygous normal individual (hh), the possible genotypes and phenotypes of their offspring can be predicted using a Punnett square.
The Punnett square for this cross would look like this:
| H | h |
-----------------
h | Hh | hh |
-----------------
h | Hh | hh |
Probability of Passing on the Gene:
In this case, the man is heterozygous (Hh) and the woman is homozygous normal (hh).
- Hh represents the genotype of the man, meaning that there is a 50% chance of passing on the dominant gene (H) to each offspring.
- The woman's genotype is hh, indicating that she does not carry the dominant gene and cannot pass it on to her offspring.
Expected Proportion of Children with Hemolytic Jaundice:
Based on the Punnett square and the probability of passing on the gene, the expected genotypes of the offspring would be:
- 50% chance of being Hh (heterozygous carriers)
- 50% chance of being hh (homozygous normals)
Since only individuals with the Hh genotype are carriers of the hemolytic jaundice gene, the proportion of children expected to develop the disease would be 50% of the total offspring.
Therefore, the correct answer is option 'D', which states that 1/20 (or 5%) of the children would be expected to develop the hemolytic disease.
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Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer?
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Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer?.
Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Hemolytic juandice is caused due to a dominant gene but only 10 percent of the people actually develop the disease. A heterozygous man marries a homozygousnormal woman. What proportion of the children would be expected to develop the hemolytic disease ?a)1/5b)1/10c)1/15d)1/20Correct answer is option 'D'. Can you explain this answer?.
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