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यदि चक्रीय चतुर्भुज के कोण A, B, C तथा D हों, तब cos A + cos B + cos C + cos D का मान होगा
  • a)
    2 (cos A – cos C)
  • b)
    2 (cos A + cos D)
  • c)
    0
  • d)
    1
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A, B, C D , cos A + cos B + cos C + cos D a)2 (cos A – ...
cos A + cos B + cos C + cos D
= (cos A + cos C) + (cos B + cos D)
= 2 cos A + C / 2 cos A – C/ 2 + 2 cos B + D / 2 cos B + D / 2
= 0
(∴0 तथा 0 चक्रीय चतुर्भुज के आमने सामने के कोण हैं।)
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A, B, C D , cos A + cos B + cos C + cos D a)2 (cos A – cos C)b)2 (cos A + cos D)c)0d)1Correct answer is option 'C'. Can you explain this answer?
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