If it start from origin than it displace 10 m towards west..Solve it in form vector like disp. in north so 20j^

Displacement from the Original Position:

To find the displacement from the original position, we need to calculate the net distance and direction traveled by the person.

Step 1: Analyzing the Directions
Let's break down the given directions into their respective components:

- 30m North: This means the person moved directly upwards along the North direction, resulting in a displacement of +30m in the y-axis.
- 20m East: This means the person moved directly towards the East, resulting in a displacement of +20m in the x-axis.
- 30√2m SW: This implies the person moved towards the Southwest direction, which is a combination of moving 30√2m towards the South and 30√2m towards the West. To calculate the individual displacements, we can use trigonometry:
- Displacement towards the South (y-axis): 30√2 * sin(45°) = 30m
- Displacement towards the West (x-axis): 30√2 * cos(45°) = 30m

Step 2: Calculating the Net Displacement
Now, let's add up the individual displacements to find the net displacement of the person:

- Net displacement in the x-axis (horizontal): +20m (East) - 30m (West) = -10m
- Net displacement in the y-axis (vertical): +30m (North) + 30m (South) = 0m

Step 3: Combining the Displacements
The net displacement is the vector sum of the individual displacements, which can be found using the Pythagorean theorem:

Net Displacement = √[(Net displacement in x-axis)² + (Net displacement in y-axis)²]

Substituting the values:

Net Displacement = √[(-10m)² + (0m)²] = √(100m²) = 10m

So, the person's displacement from the original position is 10 meters, and it is in the west direction.

Summary:
The person's displacement from the original position is 10 meters towards the west. This means that after moving 30m north, then 20m east, and finally 30√2m southwest, the person ended up 10 meters west of their original position.