A person moves 30 m North and then 20 m towards East and finally 30√2 ...
Solution:
To find out the displacement of the person from the origin, we need to find the net distance and direction from the starting point to the final point.
Firstly, the person moves 30 m towards North.
Secondly, the person moves 20 m towards East.
Finally, the person moves 30√2 m in South West direction.
Now, let's draw a diagram to represent the above movements.
![image.png](attachment:image.png)
From the above diagram, we can see that the person has moved towards North and East, and then moved towards South West.
The person has moved towards opposite directions, so we need to find out the net distance and direction.
To find out the net distance, we need to subtract the distance moved towards South from the distance moved towards North and the distance moved towards West from the distance moved towards East.
Net distance moved towards North = 30 m
Net distance moved towards East = 20 m
Net distance moved towards South = 30√2 m
Net distance moved towards West = 0 m
Therefore, the net distance = Net distance moved towards North - Net distance moved towards South + Net distance moved towards East - Net distance moved towards West = 30 - 30√2 + 20 - 0 = -30√2 + 50 m
To find out the direction, we need to find out the angle made by the net displacement with the x-axis.
tanθ = Net distance moved towards North - Net distance moved towards South / Net distance moved towards East - Net distance moved towards West
tanθ = 30 - 30√2 / 20 - 0
tanθ = (30 - 30√2) / 20
θ = tan^-1[(30 - 30√2) / 20]
θ = 53.1°
Therefore, the displacement of the person from the origin is 30√2 - 50 m towards West and 53.1° from the x-axis.
Hence, the correct option is option C) 10 m along West.
A person moves 30 m North and then 20 m towards East and finally 30√2 ...
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