Find the value of k if the quadratic equation 3x² - k√3 x+4=0 has equal roots?

Question

Answer

P(x)=3x^2-k√3x+4=0,
given that the quadratic equation has equal roots,
so, discriminant=0,
or, b^2-4ac=0,
here, a=3,b=-k√3 and c=4,
by putting the values we get ,
(-k√3)^2-4(3)(4)=0,
3k^2-48=0,
k^2=48/3=16,
k=+√16 or, -√16=4 or -4

Answer

4 or - 4

Answer

B-4ac=oans . 4 or -4

Answer

Here....3x² - k√3x + 4 = 0...where...a = 3 , b = -k√3 , c = 4...put it on quadratic....b² - 4ac = 0then...(-k√3)² - 4×3×4 = 03k² - 48 = 03k² - 48k² = ± 16k = ± 4k = 4 , - 4.. Hence...answer will be 4 and -4 ....ok

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