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A radioactive nucleus undergoes spontaneous decay in the sequencewhere Z is the atomic number of element X. The possible decay particles in the sequence are:
  • a)
    α, β-, β+
  • b)
    α, β+, β-
  • c)
    β+, α, β
  • d)
    β-, α, β+
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A radioactive nucleus undergoes spontaneous decay in the sequencewhere...
As we know due to α-decay atomic number decreases by 2 and mass number decreases by 4. Due to β− decay mass number remains unchange and atomic number increases by 1.
Due to  β+ decay mass number remains unchange but atomic number decreares by 1.
So, option (3) is correct option.
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A radioactive nucleus undergoes spontaneous decay in the sequencewhere Z is the atomic number of element X. The possible decay particles in the sequence are:a)α,β-,β+b)α,β+,β-c)β+, α,βd)β-,α,β+Correct answer is option 'C'. Can you explain this answer?
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