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Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution?
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Allele frequency for a dominant allele is 0.2. what will be the number...
**Solution:**
To find the number of dead organisms due to the lethal homozygous recessive condition, we need to first calculate the frequency of the recessive allele.
Let's assume the dominant allele is represented by "A" and the recessive allele is represented by "a". The frequency of the dominant allele (A) is given as 0.2.
Since there are only two alleles in the population (A and a), the total frequency of alleles in the population must be equal to 1. So, we can calculate the frequency of the recessive allele (a) as follows:
Frequency of A + Frequency of a = 1
0.2 + Frequency of a = 1
Frequency of a = 1 - 0.2
Frequency of a = 0.8
Now, we can calculate the frequency of the homozygous recessive genotype (aa). The frequency of the homozygous recessive genotype is simply the square of the frequency of the recessive allele, as both alleles need to be present in an individual for the lethal homozygous recessive condition to occur.
Frequency of aa = (Frequency of a)^2
Frequency of aa = 0.8^2
Frequency of aa = 0.64
To calculate the number of individuals with the lethal homozygous recessive condition, we can multiply the frequency of the homozygous recessive genotype by the total population size.
Number of individuals with aa = Frequency of aa * Total population size
Number of individuals with aa = 0.64 * 1000
Number of individuals with aa = 640
Therefore, the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition is 640.
The correct answer is **a) 640**.
To find the number of dead organisms due to the lethal homozygous recessive condition, we need to first calculate the frequency of the recessive allele.
Let's assume the dominant allele is represented by "A" and the recessive allele is represented by "a". The frequency of the dominant allele (A) is given as 0.2.
Since there are only two alleles in the population (A and a), the total frequency of alleles in the population must be equal to 1. So, we can calculate the frequency of the recessive allele (a) as follows:
Frequency of A + Frequency of a = 1
0.2 + Frequency of a = 1
Frequency of a = 1 - 0.2
Frequency of a = 0.8
Now, we can calculate the frequency of the homozygous recessive genotype (aa). The frequency of the homozygous recessive genotype is simply the square of the frequency of the recessive allele, as both alleles need to be present in an individual for the lethal homozygous recessive condition to occur.
Frequency of aa = (Frequency of a)^2
Frequency of aa = 0.8^2
Frequency of aa = 0.64
To calculate the number of individuals with the lethal homozygous recessive condition, we can multiply the frequency of the homozygous recessive genotype by the total population size.
Number of individuals with aa = Frequency of aa * Total population size
Number of individuals with aa = 0.64 * 1000
Number of individuals with aa = 640
Therefore, the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition is 640.
The correct answer is **a) 640**.
Community Answer
Allele frequency for a dominant allele is 0.2. what will be the number...
P=0.2 (dom.)q=0.8 (rec.)p^2+q^2+2pq=1Here, we need to find q^2q=0.8q^2=0.64Therefore, out of 1000 peoplerecessive genotype having population is0.64*1000=640
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Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution?
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Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution?.
Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Allele frequency for a dominant allele is 0.2. what will be the number of dead organisms out of a population of 1000 individuals due to the lethal homozygous recessive condition:- a)640 b)900 c)800 d)840. plz solve step wise. and post the solution?.
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