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If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48?
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If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidif...
Solution:
Given Data:
Volume of H2O2 solution = 5.0 cm3
Mass of iodine liberated = 0.508 g
To Find:
Volume strength of H2O2 solution
Concept Used:
H2O2 reacts with KI in acidic medium to liberate iodine. The reaction is as follows:
H2O2 + 2KI + H2SO4 → I2 + 2KHSO4 + 2H2O
From the above equation, we can say that 1 mole of H2O2 liberates 1 mole of I2.
The volume strength of H2O2 solution is defined as the volume of oxygen liberated by the decomposition of 1 mL of H2O2 solution.
Solution:
We know that 1 gram-molecule of any gas at STP occupies 22.4 L volume.
Also, 1 mole of O2 is liberated by the decomposition of 1 mole of H2O2.
Therefore, the volume of O2 liberated by the decomposition of 1 mL of H2O2 solution can be given as:
V = 22.4 × (1/2) × (1/1000) = 0.0112 L = 11.2 mL
Now, let us calculate the number of moles of I2 liberated by the reaction:
Molar mass of I2 = 2 × 126.9 g/mol = 253.8 g/mol
Number of moles of I2 = 0.508/253.8 = 0.002 mol
From the equation of the reaction, we can say that 1 mole of H2O2 liberates 1 mole of I2.
Therefore, the number of moles of H2O2 present in 5.0 cm3 of the solution can be given as:
Number of moles of H2O2 = 0.002 mol
The volume strength of H2O2 solution can be defined as the volume of oxygen liberated by the decomposition of 1 mL of H
Given Data:
Volume of H2O2 solution = 5.0 cm3
Mass of iodine liberated = 0.508 g
To Find:
Volume strength of H2O2 solution
Concept Used:
H2O2 reacts with KI in acidic medium to liberate iodine. The reaction is as follows:
H2O2 + 2KI + H2SO4 → I2 + 2KHSO4 + 2H2O
From the above equation, we can say that 1 mole of H2O2 liberates 1 mole of I2.
The volume strength of H2O2 solution is defined as the volume of oxygen liberated by the decomposition of 1 mL of H2O2 solution.
Solution:
We know that 1 gram-molecule of any gas at STP occupies 22.4 L volume.
Also, 1 mole of O2 is liberated by the decomposition of 1 mole of H2O2.
Therefore, the volume of O2 liberated by the decomposition of 1 mL of H2O2 solution can be given as:
V = 22.4 × (1/2) × (1/1000) = 0.0112 L = 11.2 mL
Now, let us calculate the number of moles of I2 liberated by the reaction:
Molar mass of I2 = 2 × 126.9 g/mol = 253.8 g/mol
Number of moles of I2 = 0.508/253.8 = 0.002 mol
From the equation of the reaction, we can say that 1 mole of H2O2 liberates 1 mole of I2.
Therefore, the number of moles of H2O2 present in 5.0 cm3 of the solution can be given as:
Number of moles of H2O2 = 0.002 mol
The volume strength of H2O2 solution can be defined as the volume of oxygen liberated by the decomposition of 1 mL of H
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If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48?
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If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48?.
If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 5.0 cm^3 olution of H2O2 liberates 0.508 g of iodine from an acidify KIsolution the volume strength of H2O2 will be (1) 10.2 (2) 8.46 (3) 5.42 (4) 4.48?.
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