NEET Exam > NEET Questions > Elimination of bromine from 2-bromobutane res...
Start Learning for Free
Elimination of bromine from 2-bromobutane results in the formation of
- a)Predominantly 2-butene
- b)Equimolar mixture of 1 and 2-butene
- c)Predominantly 1-butene
- d)Predominantly 2-butyne.
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Elimination of bromine from 2-bromobutane results in the formation ofa...
2-bromobutane → CH3CH = CHCH3 + CH3CH2CH=CH2
The major product follows Saytzeff rule.
Hence option (A) is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
Elimination of bromine from 2-bromobutane results in the formation ofa...
Elimination of Bromine from 2-Bromobutane
The elimination reaction of bromine from 2-bromobutane is a type of E2 (bimolecular elimination) reaction. During this reaction, the bromine atom is removed from the carbon chain, resulting in the formation of a double bond.
E2 Reaction Mechanism
The E2 reaction occurs in a single step, involving the simultaneous removal of a proton and a leaving group (in this case, bromine) from adjacent carbon atoms. The leaving group takes a pair of electrons from the carbon-hydrogen bond, forming a double bond between the two carbon atoms.
The reaction mechanism can be summarized as follows:
1. The base (usually a strong base such as hydroxide ion, OH-) approaches the hydrogen atom on the carbon adjacent to the bromine atom.
2. The base abstracts the proton, creating a carbanion intermediate and leaving a bromide ion.
3. The carbanion intermediate then rearranges to form the most stable alkene through a transition state.
4. Finally, the bromide ion combines with a proton from the solvent to form HBr.
Stability of Alkenes
The stability of alkenes is determined by the degree of substitution at the double bond. The more substituted the double bond, the more stable the alkene. This stability is due to the increased electron density around the double bond, which is provided by the alkyl groups attached to the carbon atoms.
Explanation of the Correct Answer
In the case of 2-bromobutane, elimination of bromine results in the formation of 2-butene. This is because the double bond in 2-butene is more substituted than the double bond in 1-butene. Therefore, the stability of the alkene product, 2-butene, is higher compared to that of 1-butene.
The stability of alkenes follows the order: tertiary > secondary > primary. In 2-butene, the double bond is formed between two secondary carbons, making it more stable than 1-butene, which has a double bond between a primary and a secondary carbon.
Hence, the correct answer is option 'A' - Predominantly 2-butene.
It is important to note that while the formation of 2-butene is favored, a small amount of 1-butene may also be formed as a minor product due to the presence of a primary carbon adjacent to the double bond. However, the major product will be 2-butene.
The elimination reaction of bromine from 2-bromobutane is a type of E2 (bimolecular elimination) reaction. During this reaction, the bromine atom is removed from the carbon chain, resulting in the formation of a double bond.
E2 Reaction Mechanism
The E2 reaction occurs in a single step, involving the simultaneous removal of a proton and a leaving group (in this case, bromine) from adjacent carbon atoms. The leaving group takes a pair of electrons from the carbon-hydrogen bond, forming a double bond between the two carbon atoms.
The reaction mechanism can be summarized as follows:
1. The base (usually a strong base such as hydroxide ion, OH-) approaches the hydrogen atom on the carbon adjacent to the bromine atom.
2. The base abstracts the proton, creating a carbanion intermediate and leaving a bromide ion.
3. The carbanion intermediate then rearranges to form the most stable alkene through a transition state.
4. Finally, the bromide ion combines with a proton from the solvent to form HBr.
Stability of Alkenes
The stability of alkenes is determined by the degree of substitution at the double bond. The more substituted the double bond, the more stable the alkene. This stability is due to the increased electron density around the double bond, which is provided by the alkyl groups attached to the carbon atoms.
Explanation of the Correct Answer
In the case of 2-bromobutane, elimination of bromine results in the formation of 2-butene. This is because the double bond in 2-butene is more substituted than the double bond in 1-butene. Therefore, the stability of the alkene product, 2-butene, is higher compared to that of 1-butene.
The stability of alkenes follows the order: tertiary > secondary > primary. In 2-butene, the double bond is formed between two secondary carbons, making it more stable than 1-butene, which has a double bond between a primary and a secondary carbon.
Hence, the correct answer is option 'A' - Predominantly 2-butene.
It is important to note that while the formation of 2-butene is favored, a small amount of 1-butene may also be formed as a minor product due to the presence of a primary carbon adjacent to the double bond. However, the major product will be 2-butene.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer?
Question Description
Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer?.
Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer?.
Solutions for Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Elimination of bromine from 2-bromobutane results in the formation ofa)Predominantly 2-buteneb)Equimolar mixture of 1 and 2-butenec)Predominantly 1-butened)Predominantly 2-butyne.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup