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Two forces F1=5N and f2=15N are acting on a body in opposite direction. If the body is placed by 5m in the direction of net force, what will be the work done by F1?
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Two forces F1=5N and f2=15N are acting on a body in opposite direction...
**Solution:**

Given:
- Force F1 = 5N
- Force F2 = 15N (opposite direction)

To find:
- Work done by force F1

**Calculating the net force:**

Since the two forces are acting in opposite directions, we can find the net force by subtracting the smaller force from the larger force.

Net force = | F2 - F1 |
= | 15N - 5N |
= | 10N |
= 10N (magnitude)

**Calculating the displacement:**

The body is placed by 5m in the direction of the net force. This means that the displacement is 5m.

Displacement = 5m

**Calculating the work done:**

The work done by a force can be calculated using the formula:

Work done = Force * Displacement * cos(theta)

Where theta is the angle between the force and displacement vectors. Since the force and displacement vectors are in the same direction, the angle theta is 0 degrees.

Therefore, the formula becomes:

Work done = Force * Displacement * cos(0)
= Force * Displacement

Substituting the values:

Work done by F1 = 5N * 5m
= 25 Nm
= 25 Joules

Therefore, the work done by the force F1 is 25 Joules.
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