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A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?
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A circular coil of radius 4cm and of 2oturns carries a current of 3 am...
Magnetic Dipole Moment of a Circular Coil

The magnetic dipole moment of a circular coil is a measure of its ability to interact with a magnetic field. It is defined as the product of the current flowing through the coil and the area enclosed by the coil.

Formula for Magnetic Dipole Moment

The formula for calculating the magnetic dipole moment of a coil is given by:

Magnetic Dipole Moment (m) = I * A

Where:
- I is the current flowing through the coil
- A is the area enclosed by the coil

Given Information
- Radius of the coil (r) = 4 cm = 0.04 m
- Number of turns (N) = 20
- Current flowing through the coil (I) = 3 A
- Magnetic field intensity (B) = 0.5 Weber/m^2

Calculation of Area Enclosed by the Coil (A)

The area enclosed by the coil can be calculated using the formula for the area of a circle:

A = π * r^2

Substituting the given values:

A = π * (0.04)^2
A = 0.005 π m^2

Calculation of Magnetic Dipole Moment (m)

Using the formula for magnetic dipole moment:

m = I * A
m = 3 * 0.005 π
m = 0.015 π A m^2

Final Answer

The magnetic dipole moment of the circular coil is 0.015 π A m^2.
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A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?
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