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A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?
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A circular coil of radius 4cm and of 2oturns carries a current of 3 am...
Magnetic Dipole Moment of a Circular Coil
The magnetic dipole moment of a circular coil is a measure of its ability to interact with a magnetic field. It is defined as the product of the current flowing through the coil and the area enclosed by the coil.
Formula for Magnetic Dipole Moment
The formula for calculating the magnetic dipole moment of a coil is given by:
Magnetic Dipole Moment (m) = I * A
Where:
- I is the current flowing through the coil
- A is the area enclosed by the coil
Given Information
- Radius of the coil (r) = 4 cm = 0.04 m
- Number of turns (N) = 20
- Current flowing through the coil (I) = 3 A
- Magnetic field intensity (B) = 0.5 Weber/m^2
Calculation of Area Enclosed by the Coil (A)
The area enclosed by the coil can be calculated using the formula for the area of a circle:
A = π * r^2
Substituting the given values:
A = π * (0.04)^2
A = 0.005 π m^2
Calculation of Magnetic Dipole Moment (m)
Using the formula for magnetic dipole moment:
m = I * A
m = 3 * 0.005 π
m = 0.015 π A m^2
Final Answer
The magnetic dipole moment of the circular coil is 0.015 π A m^2.
The magnetic dipole moment of a circular coil is a measure of its ability to interact with a magnetic field. It is defined as the product of the current flowing through the coil and the area enclosed by the coil.
Formula for Magnetic Dipole Moment
The formula for calculating the magnetic dipole moment of a coil is given by:
Magnetic Dipole Moment (m) = I * A
Where:
- I is the current flowing through the coil
- A is the area enclosed by the coil
Given Information
- Radius of the coil (r) = 4 cm = 0.04 m
- Number of turns (N) = 20
- Current flowing through the coil (I) = 3 A
- Magnetic field intensity (B) = 0.5 Weber/m^2
Calculation of Area Enclosed by the Coil (A)
The area enclosed by the coil can be calculated using the formula for the area of a circle:
A = π * r^2
Substituting the given values:
A = π * (0.04)^2
A = 0.005 π m^2
Calculation of Magnetic Dipole Moment (m)
Using the formula for magnetic dipole moment:
m = I * A
m = 3 * 0.005 π
m = 0.015 π A m^2
Final Answer
The magnetic dipole moment of the circular coil is 0.015 π A m^2.
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A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?
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A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?.
A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular coil of radius 4cm and of 2oturns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5weber/m2 . The magnetic dipole moment of the coil?.
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