NEET Exam > NEET Questions > 58 ml of N/5 H2S04 are used to neutralize amm...
Start Learning for Free
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6?
Most Upvoted Answer
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of o...
Calculation of Percentage of Nitrogen in Organic Compound
Therefore, the percentage of Nitrogen in the organic compound is 16.2%.
- Given volume of N/5 H2S04 used = 58 ml
- Let x be the number of moles of N in the organic compound
- Number of moles of H2S04 used = (N/5) x 0.058
- From the balanced chemical equation, 1 mole of H2S04 reacts with 2 moles of NH3
- Therefore, number of moles of NH3 produced = 2 x (N/5) x 0.058
- Mass of NH3 produced = 2 x (N/5) x 0.058 x 17 (molar mass of NH3)
- Given mass of organic compound = 1 gram
- Therefore, percentage of N in organic compound = (mass of N/mass of organic compound) x 100
- mass of N = percentage of N x mass of organic compound/100
- Equating the moles of N in organic compound and NH3 produced,
- x = 2 x (N/5) x 0.058 x 14 (molar mass of N)
- Substituting for x and mass of NH3 in the above equation,
- mass of N = (68.8/mass of organic compound) x 100
- Given percentage of N in organic compound can be calculated by substituting different values of mass of organic compound and checking which gives the correct percentage of N.
Therefore, the percentage of Nitrogen in the organic compound is 16.2%.
Community Answer
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of o...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6?
Question Description
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6?.
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6?.
Solutions for 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? defined & explained in the simplest way possible. Besides giving the explanation of
58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6?, a detailed solution for 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? has been provided alongside types of 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? theory, EduRev gives you an
ample number of questions to practice 58 ml of N/5 H2S04 are used to neutralize ammonia given by 1 gram of organic compound .percentage of Nitrogen in the compound is 34.3 82.7 16.2 21.6? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup