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What is the number of atoms present in 224 dm3 of oxygen gas?
- a)6.023 x 1024
- b)1.201 x 1024
- c)5.023 x 1025
- d)1.203 x 1026
Correct answer is option 'A'. Can you explain this answer?
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What is the number of atoms present in 224 dm3 of oxygen gas?a)6.023 x...
Calculation of Number of Atoms in 224 dm3 of Oxygen Gas
To calculate the number of atoms present in 224 dm3 of oxygen gas, we need to follow these steps:
1. Determine the Volume of 1 Mole of Oxygen Gas
- The molar volume of any gas at standard temperature and pressure (STP) is 22.4 dm3.
2. Calculate the Number of Moles of Oxygen Gas in 224 dm3
- Number of moles = Volume of oxygen gas / Molar volume
- Number of moles = 224 dm3 / 22.4 dm3/mol
- Number of moles = 10 moles
3. Determine the Avogadro's Number
- Avogadro's number is 6.023 x 10^23, which represents the number of entities in one mole of a substance.
4. Calculate the Number of Atoms in 10 Moles of Oxygen Gas
- Number of atoms = Number of moles x Avogadro's number
- Number of atoms = 10 moles x 6.023 x 10^23
- Number of atoms = 6.023 x 10^24
Therefore, the number of atoms present in 224 dm3 of oxygen gas is 6.023 x 10^24 (option A).
To calculate the number of atoms present in 224 dm3 of oxygen gas, we need to follow these steps:
1. Determine the Volume of 1 Mole of Oxygen Gas
- The molar volume of any gas at standard temperature and pressure (STP) is 22.4 dm3.
2. Calculate the Number of Moles of Oxygen Gas in 224 dm3
- Number of moles = Volume of oxygen gas / Molar volume
- Number of moles = 224 dm3 / 22.4 dm3/mol
- Number of moles = 10 moles
3. Determine the Avogadro's Number
- Avogadro's number is 6.023 x 10^23, which represents the number of entities in one mole of a substance.
4. Calculate the Number of Atoms in 10 Moles of Oxygen Gas
- Number of atoms = Number of moles x Avogadro's number
- Number of atoms = 10 moles x 6.023 x 10^23
- Number of atoms = 6.023 x 10^24
Therefore, the number of atoms present in 224 dm3 of oxygen gas is 6.023 x 10^24 (option A).
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Community Answer
What is the number of atoms present in 224 dm3 of oxygen gas?a)6.023 x...
Number of atoms = Given volume/Volume given at STP x 6.023 x 1023
1 dm3 = 1 L
or 224 dm3 = 224 L
Number of atoms = 224/22.4 x 6.023 x 1023
= 6.023 x 1024
1 dm3 = 1 L
or 224 dm3 = 224 L
Number of atoms = 224/22.4 x 6.023 x 1023
= 6.023 x 1024
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What is the number of atoms present in 224 dm3 of oxygen gas?a)6.023 x 1024b)1.201 x 1024c)5.023 x 1025d)1.203 x 1026Correct answer is option 'A'. Can you explain this answer?
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