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Arrange Increasing order of Bond Angle 1)OCl2 2)H2O 3)OF2?
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Arrange Increasing order of Bond Angle 1)OCl2 2)H2O 3)OF2?
Increasing order of Bond Angle: OCl2, H2O, OF2



  • OF2: The bond angle of OF2 is the smallest among the given molecules. It has a bond angle of approximately 103 degrees. This is due to the presence of two lone pairs on the oxygen atom which exert repulsion on the bonded fluorine atoms. The lone pairs occupy more space as compared to the bonded pairs, thereby reducing the bond angle.


  • H2O: The bond angle of H2O is larger than that of OF2 and is approximately 104.5 degrees. This is due to the presence of two lone pairs on the oxygen atom which exert repulsion on the bonded hydrogen atoms. However, the bond angle is slightly less than the ideal bond angle of 109.5 degrees due to the presence of two lone pairs.


  • OCl2: The bond angle of OCl2 is the largest among the given molecules and is approximately 110 degrees. This is due to the presence of two chlorine atoms which are larger in size than the fluorine atoms. The larger size of the chlorine atoms results in more space between the bonded pairs, thereby increasing the bond angle.



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Arrange Increasing order of Bond Angle 1)OCl2 2)H2O 3)OF2?
H2o>ocl2>of2
this is coz when the central atom is same more the electronegativvity of the surrounding angle less will be the bond angle generally
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