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An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.?
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An electron tube was sealed off during manufacture at a pressure of 1....
Calculation of the Number of Molecules in the Electron Tube
To find the number of molecules remaining in the electron tube, we need to use the ideal gas law equation. The ideal gas law relates the pressure, volume, temperature, and number of gas molecules in a system. The equation is given by:
PV = nRT
Where:
P = pressure
V = volume
n = number of molecules
R = ideal gas constant
T = temperature
Step 1: Convert pressure to SI units
The pressure given in the problem is 1.2 * 10^-7 mm Hg. We need to convert it to SI units, which is Pascal (Pa). The conversion factor is 1 mm Hg = 133.322 Pa.
1.2 * 10^-7 mm Hg * 133.322 Pa / 1 mm Hg = 1.60 * 10^-5 Pa
Step 2: Convert volume to SI units
The volume given in the problem is 100 cm^3. We need to convert it to SI units, which is cubic meters (m^3). The conversion factor is 1 cm^3 = 1 * 10^-6 m^3.
100 cm^3 * 1 * 10^-6 m^3 / 1 cm^3 = 1 * 10^-4 m^3
Step 3: Convert temperature to Kelvin
The temperature given in the problem is 27 degrees Celsius. We need to convert it to Kelvin (K). The conversion formula is K = °C + 273.15.
27 °C + 273.15 = 300.15 K
Step 4: Calculate the number of molecules
Now that we have all the necessary values in SI units, we can rearrange the ideal gas law equation to solve for the number of molecules (n):
n = PV / RT
n = (1.60 * 10^-5 Pa) * (1 * 10^-4 m^3) / (8.314 J/mol·K * 300.15 K)
n ≈ 6.09 * 10^16 molecules
Therefore, the number of molecules remaining in the electron tube is approximately 6.09 * 10^16 molecules.
To find the number of molecules remaining in the electron tube, we need to use the ideal gas law equation. The ideal gas law relates the pressure, volume, temperature, and number of gas molecules in a system. The equation is given by:
PV = nRT
Where:
P = pressure
V = volume
n = number of molecules
R = ideal gas constant
T = temperature
Step 1: Convert pressure to SI units
The pressure given in the problem is 1.2 * 10^-7 mm Hg. We need to convert it to SI units, which is Pascal (Pa). The conversion factor is 1 mm Hg = 133.322 Pa.
1.2 * 10^-7 mm Hg * 133.322 Pa / 1 mm Hg = 1.60 * 10^-5 Pa
Step 2: Convert volume to SI units
The volume given in the problem is 100 cm^3. We need to convert it to SI units, which is cubic meters (m^3). The conversion factor is 1 cm^3 = 1 * 10^-6 m^3.
100 cm^3 * 1 * 10^-6 m^3 / 1 cm^3 = 1 * 10^-4 m^3
Step 3: Convert temperature to Kelvin
The temperature given in the problem is 27 degrees Celsius. We need to convert it to Kelvin (K). The conversion formula is K = °C + 273.15.
27 °C + 273.15 = 300.15 K
Step 4: Calculate the number of molecules
Now that we have all the necessary values in SI units, we can rearrange the ideal gas law equation to solve for the number of molecules (n):
n = PV / RT
n = (1.60 * 10^-5 Pa) * (1 * 10^-4 m^3) / (8.314 J/mol·K * 300.15 K)
n ≈ 6.09 * 10^16 molecules
Therefore, the number of molecules remaining in the electron tube is approximately 6.09 * 10^16 molecules.
Community Answer
An electron tube was sealed off during manufacture at a pressure of 1....
3.86*10"11
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An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.?
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An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.?.
An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron tube was sealed off during manufacture at a pressure of 1.2*10^-7mm of hg at 27 Degree Celsius. it's volume is 100 cm3. the number of molecules remain in the tube is? plz. anyone answer this.?.
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