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Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?
a)(2P/3)^3/2
b)2(P/3)^3/2?
c)P^3/2?
a)(2P/3)^3/2
b)2(P/3)^3/2?
c)P^3/2?
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Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s...
The given equation represents the dissociation of Ag2CO3(s) into Ag(s), CO2(g), and O2(g). At a given temperature of 1200 K, the reaction proceeds in the forward direction.
At equilibrium, the total pressure in the flask is represented as P atm. This means that the sum of the partial pressures of all the gases present in the flask is equal to P atm.
Kp is the equilibrium constant expressed in terms of partial pressures. It is calculated by taking the partial pressures of the products raised to their stoichiometric coefficients and dividing it by the partial pressures of the reactants raised to their stoichiometric coefficients.
To calculate Kp for the given reaction, we need to express the equilibrium constant in terms of partial pressures. The equation is:
Kp = (P(Ag)^2 * P(CO2) * P(O2)) / (P(Ag2CO3))
where P(Ag), P(CO2), P(O2), and P(Ag2CO3) represent the partial pressures of Ag, CO2, O2, and Ag2CO3 respectively.
In this equation, we can see that the partial pressure of Ag2CO3 is in the denominator, indicating that an increase in the partial pressure of Ag2CO3 will result in a decrease in the value of Kp. This suggests that the dissociation of Ag2CO3 is favored at lower partial pressures of Ag2CO3.
On the other hand, an increase in the partial pressures of Ag, CO2, and O2 in the numerator will result in an increase in the value of Kp. This indicates that the formation of Ag, CO2, and O2 is favored at higher partial pressures of these gases.
Therefore, to increase the value of Kp, one needs to increase the partial pressures of Ag, CO2, and O2, while decreasing the partial pressure of Ag2CO3.
In summary, the equilibrium constant Kp for the given reaction can be calculated using the equation provided, and it is dependent on the partial pressures of Ag, CO2, O2, and Ag2CO3. Manipulating these partial pressures can affect the value of Kp.
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Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2?
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Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2?.
Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ag2CO3(s) is dissociated in a 1L sealed flask at 1200 K as Ag2CO3(s) 2Ag(s) CO2(g) 21O2(g) Total pressure set up at equilibrium is P atm. Kp is:?a)(2P/3)^3/2b)2(P/3)^3/2?c)P^3/2?.
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