How to calculate bond order of 1. N2O4?

Question

Answer

Calculating Bond Order of N2O4

Bond order is a measure of the number of chemical bonds between a pair of atoms. It is calculated by taking the difference between the number of bonding electrons and the number of anti-bonding electrons, and then dividing by two. In the case of N2O4, we can calculate the bond order using the following steps:

Step 1: Draw the Lewis Structure

The first step in calculating bond order is to draw the Lewis structure of the molecule. In the case of N2O4, we have:

Step 2: Determine the Number of Electrons

The next step is to count the number of electrons in the molecule. In N2O4, we have:

Each nitrogen atom has 5 valence electrons

Oxygen has 6 valence electrons

So the total number of electrons in the molecule is:

2(N) + 4(O) = 28 electrons

Step 3: Determine the Bonding and Anti-bonding Electrons

Next, we need to determine the number of bonding and anti-bonding electrons in the molecule. This can be done by filling the molecular orbitals in order of increasing energy. The molecular orbital diagram for N2O4 is:

In this diagram:

The filled orbitals are shown in blue

The half-filled orbitals are shown in purple

The empty orbitals are shown in white

From this diagram, we can see that:

There are 10 bonding electrons

There are 4 anti-bonding electrons

Step 4: Calculate Bond Order

Finally, we can calculate the bond order using the formula:

Bond Order = (Number of Bonding Electrons - Number of Anti-bonding Electrons) / 2

For N2O4, we have:

Bond Order = (10 - 4) / 2 = 3

Step 5: Interpret the Results

The bond order of 3 indicates that there are 3 chemical bonds between the two nitrogen atoms in N2O4. This makes sense, as the Lewis structure shows two nitrogen atoms connected by a triple bond.

Answer

First of draw the resonating structure of n2o4that is 4 and then divide 6 bonding electrons to the four resonating structure that is 6/4=1.5

Answer

Hey saini first of all find the no of charge on n2o4 which is minus then find no of charge delocalised on how many atom which is 1/4 to every oxygen and then sum the delocalised pie bondto one where 1is being added for sigma character which is always 100% so 1/2 +1=1.5or another method the easiest method draw the resonating structure of n2o4that  is four . then lastly decide six bonding of n2o4 to by four resonating structure.

Answer

Bond order= No. of covalent bonds÷ No. of resonating structures

Answer

1.5

Answer

Is it 1.5

Answer

1.5

Answer

Thanx

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