4 octahedral voids..in CCP / FCC lattice atoms are present at corners and face of a cube so atoms present at corners = 8* 1\8 = 1atoms present on faces = 6* 1\2 = 3 total atoms present = 3+1=4 octahedral voids are equal to the total no. of atom in a cube and tetrahedral voids are twice the total no. of atoms in a cube hope it helps.....

Finding the Number of Octahedral Voids in Cubic Close Packed Structure

To find the number of octahedral voids per atom present in cubic close packed structure, we can follow the following steps:

Step 1: Understand the Definition of Octahedral Voids
Octahedral voids are the void spaces that are present between six atoms that are arranged octahedrally around a central atom in a crystal lattice structure.

Step 2: Understand the Definition of Cubic Close Packed Structure
Cubic close packed structure is a crystal lattice structure in which the atoms are arranged in a face-centered cubic lattice with additional layers of atoms stacked on top of each other.

Step 3: Determine the Number of Atoms in a Cubic Close Packed Structure
In a cubic close packed structure, there are a total of four atoms per unit cell.

Step 4: Determine the Number of Octahedral Voids in a Cubic Close Packed Structure
In a cubic close packed structure, there are a total of four octahedral voids per unit cell. Therefore, the number of octahedral voids per atom is 4/4 = 1.

Step 5: Choose the Correct Option
Based on the above calculations, the correct option is (a) 1.

In summary, to find the number of octahedral voids per atom present in cubic close packed structure, we need to understand the definitions of octahedral voids and cubic close packed structure, determine the number of atoms in a cubic close packed structure, determine the number of octahedral voids in a cubic close packed structure, and choose the correct option based on the calculations.