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Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)?
Most Upvoted Answer
Equal Moles of Hydrogen and oxygen gases are placed in a container wit...
**Solution:**
To solve this problem, we need to understand the concept of mole ratios and the behavior of gases.
**Mole Ratios:**
In a balanced chemical equation, the coefficients represent the ratio of moles of reactants and products. For example, in the balanced equation for the reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O):
2H2 + O2 ⟶ 2H2O
The ratio of moles of hydrogen gas to moles of oxygen gas is 2:1.
**Behavior of Gases:**
Gases tend to behave independently of each other. In a container, gas molecules move randomly and collide with each other and the walls of the container. The rate at which a gas escapes from a container depends on its average speed, which is determined by its molar mass. Lighter gases tend to have higher average speeds and escape more quickly.
**Solution Steps:**
1. Let's assume we have 1 mole of hydrogen gas (H2) and 1 mole of oxygen gas (O2) initially in the container.
2. According to the mole ratio in the balanced equation, for every 2 moles of hydrogen gas that escape, 1 mole of oxygen gas should escape.
3. Since the rate of escape is determined by the average speed of the gas molecules, we can assume that the hydrogen gas escapes twice as fast as the oxygen gas.
4. Let's consider the time required for half of the hydrogen gas to escape. During this time, the hydrogen gas escapes at a rate twice as fast as the oxygen gas.
5. Therefore, if the time required for half of the hydrogen gas to escape is t, the oxygen gas will only have half the time to escape, which is t/2.
6. Now, we can calculate the fraction of oxygen gas that escapes in the time t/2. Since the rate of escape is directly proportional to time, the fraction of oxygen gas that escapes in t/2 is equal to (t/2) / t = 1/2.
7. Therefore, the correct answer is d. 1/2.
**Conclusion:**
In the time required for one half of the hydrogen gas to escape, only one half of the oxygen gas escapes. This can be explained by the mole ratio in the balanced equation and the behavior of gases.
To solve this problem, we need to understand the concept of mole ratios and the behavior of gases.
**Mole Ratios:**
In a balanced chemical equation, the coefficients represent the ratio of moles of reactants and products. For example, in the balanced equation for the reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O):
2H2 + O2 ⟶ 2H2O
The ratio of moles of hydrogen gas to moles of oxygen gas is 2:1.
**Behavior of Gases:**
Gases tend to behave independently of each other. In a container, gas molecules move randomly and collide with each other and the walls of the container. The rate at which a gas escapes from a container depends on its average speed, which is determined by its molar mass. Lighter gases tend to have higher average speeds and escape more quickly.
**Solution Steps:**
1. Let's assume we have 1 mole of hydrogen gas (H2) and 1 mole of oxygen gas (O2) initially in the container.
2. According to the mole ratio in the balanced equation, for every 2 moles of hydrogen gas that escape, 1 mole of oxygen gas should escape.
3. Since the rate of escape is determined by the average speed of the gas molecules, we can assume that the hydrogen gas escapes twice as fast as the oxygen gas.
4. Let's consider the time required for half of the hydrogen gas to escape. During this time, the hydrogen gas escapes at a rate twice as fast as the oxygen gas.
5. Therefore, if the time required for half of the hydrogen gas to escape is t, the oxygen gas will only have half the time to escape, which is t/2.
6. Now, we can calculate the fraction of oxygen gas that escapes in the time t/2. Since the rate of escape is directly proportional to time, the fraction of oxygen gas that escapes in t/2 is equal to (t/2) / t = 1/2.
7. Therefore, the correct answer is d. 1/2.
**Conclusion:**
In the time required for one half of the hydrogen gas to escape, only one half of the oxygen gas escapes. This can be explained by the mole ratio in the balanced equation and the behavior of gases.
Community Answer
Equal Moles of Hydrogen and oxygen gases are placed in a container wit...
Rate of diffusion of gas=volume of gas/time taken=root over molar massso Ra/Rb=(Va/Vb)×(tb/ta)=√mb/maVa= volume escape of H2 and Vb= volume escape of o2mb=molar mass of o2 ,ma= molar mass of h2by putting appropriate values u get ans Vb=1/8
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Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)?
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Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)?.
Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equal Moles of Hydrogen and oxygen gases are placed in a container with pin hole through which both can escape. What fraction of the oxygen escapes in the time required for one half of the Hydrogen to escape?? a.1/8 b. 1/4 c. 3/8 d. 1/2.( please give explanation with solution)?.
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