NEET Exam  >  NEET Questions  >  Calculate molarity of 98% percentage by mass ... Start Learning for Free
Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain
Most Upvoted Answer
Calculate molarity of 98% percentage by mass H2SO4 at 308K having dens...
Calculation of Molarity of H2SO4 Solution

Given:

- Percentage by mass of H2SO4 = 98%
- Density of solution = 1.84 g/mL
- Temperature of solution = 308 K

Formula:

Molarity (M) = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)

Calculation:

- Firstly, we need to calculate the molar mass of H2SO4.

Molar mass of H2SO4 = (2 x atomic mass of H) + (1 x atomic mass of S) + (4 x atomic mass of O)
= (2 x 1.0079 g/mol) + (1 x 32.066 g/mol) + (4 x 15.999 g/mol)
= 98.079 g/mol

- Now, we need to calculate the mass of H2SO4 in 1 liter of the solution.

Mass of 1 liter of solution = density x volume
= 1.84 g/mL x 1 L
= 1.84 kg

Mass of H2SO4 in 1 liter of solution = 98% of 1.84 kg
= 0.98 x 1.84 kg
= 1.8032 kg

- Finally, we can calculate the molarity of the H2SO4 solution.

Molarity of H2SO4 solution = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)
= (1803.2 g) / (98.079 g/mol) / (1 L)
= 18.42 M

Therefore, the molarity of 98% H2SO4 solution at 308 K with a density of 1.84 g/mL is 18.42 M.
Community Answer
Calculate molarity of 98% percentage by mass H2SO4 at 308K having dens...
Molar mass of H2SO4 = 98g/mol = Mm
D =density = 1.84g/cc
W/w = 98%
V = 1dm3 = 1L = 1000ml = 1000cc
Mass of solution = V x D
M = 1000 x 1.84 = 1840g per 1000cc
Using w/w, 98% of 1840g = H2SO4
= (98/100) x 1840 = 1803.2g = m
Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000cc
Thus, molarity = 18.4M (18.4mol)
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain
Question Description
Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain.
Solutions for Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain defined & explained in the simplest way possible. Besides giving the explanation of Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain, a detailed solution for Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain has been provided alongside types of Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain theory, EduRev gives you an ample number of questions to practice Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev