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30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml?
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30% w/w glucose solution is present . calculate the molarity of soluti...
Understanding the Problem
To find the molarity of a 30% w/w glucose solution with a density of 1.2 g/ml, we need to follow these steps:
Step 1: Calculate the Mass of the Solution
- A 30% w/w solution means 30 grams of glucose in 100 grams of solution.
- Therefore, the total mass of the solution is 100 grams.
Step 2: Convert Mass of the Solution to Volume
- Using the density formula: Density = Mass/Volume.
- Rearranging gives: Volume = Mass/Density.
- Volume of the solution = 100 g / 1.2 g/ml = 83.33 ml.
Step 3: Convert Volume from ml to Liters
- To convert ml to liters, divide by 1000.
- Volume in liters = 83.33 ml / 1000 = 0.08333 L.
Step 4: Calculate Moles of Glucose
- The molar mass of glucose (C6H12O6) is approximately 180 g/mol.
- Moles of glucose = Mass of glucose / Molar mass.
- Moles of glucose = 30 g / 180 g/mol = 0.1667 moles.
Step 5: Calculate Molarity
- Molarity (M) = Moles of solute / Volume of solution in liters.
- Molarity = 0.1667 moles / 0.08333 L = 2.00 M.
Final Result
- The molarity of the 30% w/w glucose solution is approximately 2.00 M.
To find the molarity of a 30% w/w glucose solution with a density of 1.2 g/ml, we need to follow these steps:
Step 1: Calculate the Mass of the Solution
- A 30% w/w solution means 30 grams of glucose in 100 grams of solution.
- Therefore, the total mass of the solution is 100 grams.
Step 2: Convert Mass of the Solution to Volume
- Using the density formula: Density = Mass/Volume.
- Rearranging gives: Volume = Mass/Density.
- Volume of the solution = 100 g / 1.2 g/ml = 83.33 ml.
Step 3: Convert Volume from ml to Liters
- To convert ml to liters, divide by 1000.
- Volume in liters = 83.33 ml / 1000 = 0.08333 L.
Step 4: Calculate Moles of Glucose
- The molar mass of glucose (C6H12O6) is approximately 180 g/mol.
- Moles of glucose = Mass of glucose / Molar mass.
- Moles of glucose = 30 g / 180 g/mol = 0.1667 moles.
Step 5: Calculate Molarity
- Molarity (M) = Moles of solute / Volume of solution in liters.
- Molarity = 0.1667 moles / 0.08333 L = 2.00 M.
Final Result
- The molarity of the 30% w/w glucose solution is approximately 2.00 M.
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30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml?
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30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml?.
30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 30% w/w glucose solution is present . calculate the molarity of solution if density of solution is 1.2 g/ml?.
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