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Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain
Most Upvoted Answer
Calculate molarity of 98% percentage by mass H2SO4 at 308K having dens...
Calculation of Molarity of H2SO4 Solution
Given:
- Percentage by mass of H2SO4 = 98%
- Density of solution = 1.84 g/mL
- Temperature of solution = 308 K
Formula:
Molarity (M) = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)
Calculation:
- Firstly, we need to calculate the molar mass of H2SO4.
Molar mass of H2SO4 = (2 x atomic mass of H) + (1 x atomic mass of S) + (4 x atomic mass of O)
= (2 x 1.0079 g/mol) + (1 x 32.066 g/mol) + (4 x 15.999 g/mol)
= 98.079 g/mol
- Now, we need to calculate the mass of H2SO4 in 1 liter of the solution.
Mass of 1 liter of solution = density x volume
= 1.84 g/mL x 1 L
= 1.84 kg
Mass of H2SO4 in 1 liter of solution = 98% of 1.84 kg
= 0.98 x 1.84 kg
= 1.8032 kg
- Finally, we can calculate the molarity of the H2SO4 solution.
Molarity of H2SO4 solution = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)
= (1803.2 g) / (98.079 g/mol) / (1 L)
= 18.42 M
Therefore, the molarity of 98% H2SO4 solution at 308 K with a density of 1.84 g/mL is 18.42 M.
Given:
- Percentage by mass of H2SO4 = 98%
- Density of solution = 1.84 g/mL
- Temperature of solution = 308 K
Formula:
Molarity (M) = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)
Calculation:
- Firstly, we need to calculate the molar mass of H2SO4.
Molar mass of H2SO4 = (2 x atomic mass of H) + (1 x atomic mass of S) + (4 x atomic mass of O)
= (2 x 1.0079 g/mol) + (1 x 32.066 g/mol) + (4 x 15.999 g/mol)
= 98.079 g/mol
- Now, we need to calculate the mass of H2SO4 in 1 liter of the solution.
Mass of 1 liter of solution = density x volume
= 1.84 g/mL x 1 L
= 1.84 kg
Mass of H2SO4 in 1 liter of solution = 98% of 1.84 kg
= 0.98 x 1.84 kg
= 1.8032 kg
- Finally, we can calculate the molarity of the H2SO4 solution.
Molarity of H2SO4 solution = (mass of solute in grams) / (molar mass of solute in grams per mole) / (volume of solution in liters)
= (1803.2 g) / (98.079 g/mol) / (1 L)
= 18.42 M
Therefore, the molarity of 98% H2SO4 solution at 308 K with a density of 1.84 g/mL is 18.42 M.
Community Answer
Calculate molarity of 98% percentage by mass H2SO4 at 308K having dens...
Molar mass of H2SO4 = 98g/mol = Mm
D =density = 1.84g/cc
W/w = 98%
V = 1dm3 = 1L = 1000ml = 1000cc
Mass of solution = V x D
M = 1000 x 1.84 = 1840g per 1000cc
Using w/w, 98% of 1840g = H2SO4
= (98/100) x 1840 = 1803.2g = m
Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000cc
Thus, molarity = 18.4M (18.4mol)
D =density = 1.84g/cc
W/w = 98%
V = 1dm3 = 1L = 1000ml = 1000cc
Mass of solution = V x D
M = 1000 x 1.84 = 1840g per 1000cc
Using w/w, 98% of 1840g = H2SO4
= (98/100) x 1840 = 1803.2g = m
Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000cc
Thus, molarity = 18.4M (18.4mol)
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Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain
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Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate molarity of 98% percentage by mass H2SO4 at 308K having density 1.84 gm/ml. Explain.
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