A diploid organism is heterozygous for 3 loci, how many type of gametes can be produced?

Question

Answer

Ya sure....if a organism is heterozygous for 3 loci mens it is hybrid for 3 characters.... so , (2 )^n   where n is hybrid character or heterozygous loci....

Answer

Number of gametes =2 power n... where n=number of heterozygotes... so ans is '8'

Answer

Answer:

There are several factors that determine the number of gametes that can be produced by a diploid organism heterozygous for 3 loci. Here are the main points to consider:

Definition of Loci:
A locus is a specific location on a chromosome where a particular gene is located. In this case, we are assuming that the organism is heterozygous for 3 different genes located on three different loci.

Mendelian Inheritance Rule:
Mendelian inheritance rules dictate that gametes will receive only one copy of each gene, which means that each gamete will only have one allele per gene.

Allele Pairing:
There are two alleles per gene, and they can combine in different ways during gamete formation. For example, if we call the alleles for locus 1 A and a, the possible pairings would be AA, Aa, and aa. The same would apply to the other two loci.

Calculating the Number of Possible Combinations:
To determine the number of possible gametes, we need to multiply the number of possible combinations for each locus. For example, if we assume that there are two possible alleles for each locus, we can use the following formula:

Number of gametes = 2^n

Where n is the number of loci. In this case, n = 3, so the number of possible gametes would be:

Number of gametes = 2^3 = 8

Therefore, a diploid organism heterozygous for 3 loci can produce 8 different types of gametes. These gametes will have different combinations of alleles for each of the three loci, resulting in a wide range of possible genetic traits for the offspring.

Answer

8

Answer

Can u explain this Sakshi ??

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