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A particle of mass 0.01 kg projected with velocity 2i m/S from point x=0; y=20 . after two seconds,it's position coordinates are? can anybody know this? please explain the solution?
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A particle of mass 0.01 kg projected with velocity 2i m/S from point x...
Problem

A particle of mass 0.01 kg is projected with velocity 2i m/s from point x=0; y=20. After two seconds, what are its position coordinates?


Solution

First, we need to find the particle's initial velocity components:


  • Initial velocity in the x-direction: Since the particle is projected with velocity 2i m/s, its initial velocity component in the x-direction is 2 m/s.

  • Initial velocity in the y-direction: The particle is projected vertically upwards, so its initial velocity component in the y-direction is 0 m/s.



Next, we need to find the particle's displacement after two seconds:


  • Displacement in the x-direction: The particle is moving with a constant velocity in the x-direction, so its displacement in the x-direction after two seconds is given by:

  • displacement = initial velocity x time

    displacement = 2 m/s x 2 s = 4 m

  • Displacement in the y-direction: The particle is moving vertically upwards under the influence of gravity. Its displacement in the y-direction after two seconds is given by:

  • displacement = initial velocity x time + 0.5 x acceleration x time^2

    displacement = 0 m/s x 2 s + 0.5 x (-9.8 m/s^2) x (2 s)^2 = -19.6 m



Finally, we can find the particle's position coordinates after two seconds:


  • Position in the x-direction: The particle's initial position in the x-direction is 0 m, and its displacement in the x-direction is 4 m. Therefore, its position in the x-direction after two seconds is:

  • x = initial position + displacement = 0 m + 4 m = 4 m

  • Position in the y-direction: The particle's initial position in the y-direction is 20 m, and its displacement in the y-direction is -19.6 m. Therefore, its position in the y-direction after two seconds is:

  • y = initial position + displacement = 20 m - 19.6 m = 0.4 m



Therefore, the particle's position coordinates after two seconds are (4 m, 0.4 m).
Community Answer
A particle of mass 0.01 kg projected with velocity 2i m/S from point x...
For x axis
s=ut + 1/2at^2 (a=0)
s=2×2
s=4
position is 4+0=4


for y axis
s=ut + 1/2at^2 (a=-10 & u =0)
s = 1/2(-10)×4
s= -20
position is 20+(-20)= 0


cordinates are (4,0)
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