Method to find hybridization of Ag in [Ag(NH3)2]Cl

To determine the hybridization of Ag in the complex [Ag(NH3)2]Cl, we need to follow a step-by-step process.

Step 1: Determine the central atom
In this complex, Ag is the central atom since it is bonded to the ligands NH3.

Step 2: Count the number of electron pairs around the central atom
The number of electron pairs around the central atom is determined by the number of ligands and any lone pairs on the central atom. In this case, Ag is bonded to two NH3 ligands, and there are no lone pairs on Ag. Therefore, the number of electron pairs around Ag is 2.

Step 3: Determine the steric number
The steric number is the sum of the number of bonded atoms and the number of lone pairs on the central atom. In this case, Ag is bonded to two NH3 ligands, and there are no lone pairs on Ag. Therefore, the steric number is 2.

Step 4: Determine the hybridization
To determine the hybridization, we can use the formula: hybridization = steric number - 1.

In this case, the steric number is 2, so the hybridization of Ag is 2 - 1 = 1. Therefore, the hybridization of Ag in [Ag(NH3)2]Cl is sp.

Step 5: Justification
The justification for the hybridization of Ag being sp can be explained by the electronic configuration and the geometry of the complex.

The electronic configuration of Ag is [Kr] 4d^10 5s^1. In the complex, Ag is bonded to two NH3 ligands, which are strong field ligands. The strong field ligands cause the 5s orbital to be destabilized, promoting the 5s electron to the 4d orbitals. As a result, the 5s orbital is empty and does not participate in bonding.

The geometry of the complex is linear, with the two NH3 ligands on opposite sides of the Ag atom. This linear geometry is consistent with the sp hybridization, where the 4d orbital and one of the 4p orbitals of Ag hybridize to form two sp hybrid orbitals.

Therefore, based on the electronic configuration and geometry, we can conclude that the hybridization of Ag in [Ag(NH3)2]Cl is sp.

NH3 is neutral ligand, so the charge on central metal Ag is +1 ( bcs of one Cl)., Ag is 4d10 5S 1..nd Ag +1 is 4d10..so 5 s is empty nd 5 p is empty.. nd Coord no is 2..so 1 s nd 1 p is used.. so it's sp.. or linear..(Ag with coordn no 2 is linear).. nd NH3 is weak or strong ligand doesn't matter here bcs d is fully filled.. btw NH3 here acts as WFL bcs of +1 charge only..