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In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please?
Most Upvoted Answer
In which of the following molecules/ions, the central atom does not in...
When the number of hybrid orbitals, H is 4, the hybridization is
where, V = number of valence electrons of central atom M = number of monovalent atoms C = total positive charge A = negative charge [a]
thus
hybridization [b] For
thus
[c] For
thus
hybridization [d] For
thus
hybridization Thus, only in
the central atom does not have sp3 hybridization.
.
where, V = number of valence electrons of central atom M = number of monovalent atoms C = total positive charge A = negative charge [a]
thus
hybridization [b] For
thus
hybridization
[c] For
thus
hybridization [d] For
thus
hybridization Thus, only in
the central atom does not have sp3 hybridization.
Community Answer
In which of the following molecules/ions, the central atom does not in...
Answer:
The central atom in the following molecules/ions does not involve a d-orbital in the hybridization process:
a) I3-
b) SF6
The central atom in both I3- and SF6 involves only s and p orbitals in the hybridization process.
On the other hand, the central atom in [Cu(NH3)4]2 and MnO4- involves d-orbitals in the hybridization process.
Explanation:
Hybridization:
Hybridization is the process in which atomic orbitals combine to form new hybrid orbitals that are energetically equivalent and have the same shape and orientation. The hybrid orbitals are used in bonding with other atoms.
The Central Atom:
In a molecule or ion, the central atom is the atom that is bonded to multiple other atoms. The hybridization of the central atom is determined by counting the number of regions of electron density around the central atom and using that to determine the hybridization of the central atom.
The Central Atom in I3-
Iodine in I3- has seven valence electrons. In I3-, there are three regions of electron density around the central iodine atom. Two of the regions are bonded to the other two iodine atoms, and one region is a lone pair of electrons.
The hybridization of the central iodine atom in I3- is sp3. In sp3 hybridization, the s orbital and three p orbitals combine to form four hybrid orbitals that are arranged in a tetrahedral geometry.
Since there are no d orbitals involved in the hybridization process of the central iodine atom, I3- is the molecule in which the central atom does not involve a d-orbital in the hybridization process.
The Central Atom in SF6
Sulfur in SF6 has six valence electrons. In SF6, there are six regions of electron density around the central sulfur atom. Each of the regions is bonded to a fluorine atom.
The hybridization of the central sulfur atom in SF6 is sp3d2. In sp3d2 hybridization, the s orbital, three p orbitals, and two d orbitals combine to form six hybrid orbitals that are arranged in an octahedral geometry.
Since there are d orbitals involved in the hybridization process of the central sulfur atom, SF6 is not the molecule in which the central atom does not involve a d-orbital in the hybridization process.
The Central Atom in [Cu(NH3)4]2
Copper in [Cu(NH3)4]2 has 11 valence electrons. In [Cu(NH3)4]2, there are four regions of electron density around the central copper atom. Each of the regions is bonded to a nitrogen atom.
The hybridization of the central copper atom in [Cu(NH3)4]2 is sp3d2. In sp3d2 hybridization, the s orbital, three p orbitals, and two d orbitals combine to form six hybrid orbitals that are arranged in an octahedral geometry.
Since there are d orbitals involved in the hybridization process of the central copper atom, [Cu(NH3)4]2 is not the molecule in which the
The central atom in the following molecules/ions does not involve a d-orbital in the hybridization process:
a) I3-
b) SF6
The central atom in both I3- and SF6 involves only s and p orbitals in the hybridization process.
On the other hand, the central atom in [Cu(NH3)4]2 and MnO4- involves d-orbitals in the hybridization process.
Explanation:
Hybridization:
Hybridization is the process in which atomic orbitals combine to form new hybrid orbitals that are energetically equivalent and have the same shape and orientation. The hybrid orbitals are used in bonding with other atoms.
The Central Atom:
In a molecule or ion, the central atom is the atom that is bonded to multiple other atoms. The hybridization of the central atom is determined by counting the number of regions of electron density around the central atom and using that to determine the hybridization of the central atom.
The Central Atom in I3-
Iodine in I3- has seven valence electrons. In I3-, there are three regions of electron density around the central iodine atom. Two of the regions are bonded to the other two iodine atoms, and one region is a lone pair of electrons.
The hybridization of the central iodine atom in I3- is sp3. In sp3 hybridization, the s orbital and three p orbitals combine to form four hybrid orbitals that are arranged in a tetrahedral geometry.
Since there are no d orbitals involved in the hybridization process of the central iodine atom, I3- is the molecule in which the central atom does not involve a d-orbital in the hybridization process.
The Central Atom in SF6
Sulfur in SF6 has six valence electrons. In SF6, there are six regions of electron density around the central sulfur atom. Each of the regions is bonded to a fluorine atom.
The hybridization of the central sulfur atom in SF6 is sp3d2. In sp3d2 hybridization, the s orbital, three p orbitals, and two d orbitals combine to form six hybrid orbitals that are arranged in an octahedral geometry.
Since there are d orbitals involved in the hybridization process of the central sulfur atom, SF6 is not the molecule in which the central atom does not involve a d-orbital in the hybridization process.
The Central Atom in [Cu(NH3)4]2
Copper in [Cu(NH3)4]2 has 11 valence electrons. In [Cu(NH3)4]2, there are four regions of electron density around the central copper atom. Each of the regions is bonded to a nitrogen atom.
The hybridization of the central copper atom in [Cu(NH3)4]2 is sp3d2. In sp3d2 hybridization, the s orbital, three p orbitals, and two d orbitals combine to form six hybrid orbitals that are arranged in an octahedral geometry.
Since there are d orbitals involved in the hybridization process of the central copper atom, [Cu(NH3)4]2 is not the molecule in which the
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In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please?
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In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please?.
In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which of the following molecules/ions, the central atom does not involved a d-orbital in the hybridization process a) I3- b) SF6 c)[Cu(NH3)4]2 d)MnO4- Detail explanation please?.
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