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The hybridisation state of the central atom and shape of the molecules is given below. Mark the incorrect combination.
- a)SO3 - sp2 hybridisation, planar triangular
- b)SO2 - sp2 hybridisation, V-shaped
- c)H2SO4 - sp2 hybridisation, V-shaped
- d)O3 - sp2 hybridisation, angular
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The hybridisation state of the central atom and shape of the molecules...
The hybridization of sulfur in H2SO4 is Sp3 and its shape square planar.
So the given statement H2SO4−sp2 hybridization and V-shaped is wrong shape.
Most Upvoted Answer
The hybridisation state of the central atom and shape of the molecules...
The correct answer is option C, H2SO4 does not have a V-shaped geometry.
Explanation:
In order to determine the hybridization state and shape of a molecule, we need to consider the number of bonding and non-bonding electron pairs around the central atom.
a) SO3:
- SO3 has a central sulfur atom bonded to three oxygen atoms.
- The sulfur atom undergoes sp2 hybridization, where one s orbital and two p orbitals hybridize to form three sp2 hybrid orbitals.
- The three sp2 hybrid orbitals are arranged in a trigonal planar geometry around the sulfur atom, with bond angles of 120 degrees.
- Therefore, SO3 has sp2 hybridization and a planar triangular shape.
b) SO2:
- SO2 also has a central sulfur atom bonded to two oxygen atoms.
- The sulfur atom undergoes sp2 hybridization, similar to SO3.
- The two sp2 hybrid orbitals and one unhybridized p orbital on sulfur form a bent shape with bond angles less than 120 degrees.
- Therefore, SO2 has sp2 hybridization and a V-shaped geometry.
c) H2SO4:
- H2SO4 consists of a central sulfur atom bonded to four oxygen atoms and two hydrogen atoms.
- The sulfur atom undergoes sp2 hybridization to form three sp2 hybrid orbitals.
- However, the fourth oxygen atom is attached to sulfur through a double bond, which requires a p orbital on sulfur to form a pi bond.
- Therefore, the sulfur atom in H2SO4 has a combination of sp2 and p hybridization.
- The molecule does not have a V-shaped geometry because the four oxygen atoms are arranged in a tetrahedral shape around the sulfur atom.
- Therefore, option C, H2SO4 having sp2 hybridization and a V-shaped geometry, is incorrect.
d) O3:
- O3 consists of three oxygen atoms.
- The central oxygen atom undergoes sp2 hybridization, similar to SO3 and SO2.
- The three sp2 hybrid orbitals are arranged in a trigonal planar geometry around the central oxygen atom.
- The two terminal oxygen atoms are bonded to the central oxygen atom through a double bond, resulting in an angular shape.
- Therefore, O3 has sp2 hybridization and an angular geometry.
In conclusion, the incorrect combination is option C, H2SO4 having sp2 hybridization and a V-shaped geometry.
Explanation:
In order to determine the hybridization state and shape of a molecule, we need to consider the number of bonding and non-bonding electron pairs around the central atom.
a) SO3:
- SO3 has a central sulfur atom bonded to three oxygen atoms.
- The sulfur atom undergoes sp2 hybridization, where one s orbital and two p orbitals hybridize to form three sp2 hybrid orbitals.
- The three sp2 hybrid orbitals are arranged in a trigonal planar geometry around the sulfur atom, with bond angles of 120 degrees.
- Therefore, SO3 has sp2 hybridization and a planar triangular shape.
b) SO2:
- SO2 also has a central sulfur atom bonded to two oxygen atoms.
- The sulfur atom undergoes sp2 hybridization, similar to SO3.
- The two sp2 hybrid orbitals and one unhybridized p orbital on sulfur form a bent shape with bond angles less than 120 degrees.
- Therefore, SO2 has sp2 hybridization and a V-shaped geometry.
c) H2SO4:
- H2SO4 consists of a central sulfur atom bonded to four oxygen atoms and two hydrogen atoms.
- The sulfur atom undergoes sp2 hybridization to form three sp2 hybrid orbitals.
- However, the fourth oxygen atom is attached to sulfur through a double bond, which requires a p orbital on sulfur to form a pi bond.
- Therefore, the sulfur atom in H2SO4 has a combination of sp2 and p hybridization.
- The molecule does not have a V-shaped geometry because the four oxygen atoms are arranged in a tetrahedral shape around the sulfur atom.
- Therefore, option C, H2SO4 having sp2 hybridization and a V-shaped geometry, is incorrect.
d) O3:
- O3 consists of three oxygen atoms.
- The central oxygen atom undergoes sp2 hybridization, similar to SO3 and SO2.
- The three sp2 hybrid orbitals are arranged in a trigonal planar geometry around the central oxygen atom.
- The two terminal oxygen atoms are bonded to the central oxygen atom through a double bond, resulting in an angular shape.
- Therefore, O3 has sp2 hybridization and an angular geometry.
In conclusion, the incorrect combination is option C, H2SO4 having sp2 hybridization and a V-shaped geometry.
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The hybridisation state of the central atom and shape of the molecules is given below. Mark the incorrect combination.a)SO3-sp2hybridisation, planar triangularb)SO2-sp2hybridisation, V-shapedc)H2SO4-sp2hybridisation, V-shapedd)O3-sp2hybridisation, angularCorrect answer is option 'C'. Can you explain this answer?
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