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16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal?
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16Kg oxygen gas expand at STP isobarically to occupy double of its ori...
USE W= PdV= nRT WHERE T =273 , R=2 AND n=16/32 u will get approximate answer
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16Kg oxygen gas expand at STP isobarically to occupy double of its ori...
Given data:
- Initial mass of oxygen gas (m) = 16 kg
- Initial volume of oxygen gas (V1) = V
- Final volume of oxygen gas (V2) = 2V
- Initial pressure (P1) = 1 atm
- Final pressure (P2) = 1 atm (isobaric process)
Calculating work done:
- Work done (W) = -PΔV
- Where ΔV = V2 - V1 = V
Substitute the values:
- Work done (W) = -PΔV
- Work done (W) = -1 atm * V
Convert atm to Joules:
- 1 atm = 101.325 J
Substitute the value of atm in Joules:
- Work done (W) = -101.325 J * V
Convert Joules to kcal:
- 1 J = 0.000239 kcal
Substitute the value of Joules in kcal:
- Work done (W) = -101.325 J * V * 0.000239 kcal
Given final volume is double the initial volume:
- V2 = 2V
Substitute the value of V2 in terms of V:
- Work done (W) = -101.325 J * 2V * 0.000239 kcal
Simplify the expression:
- Work done (W) = -0.048 kcal * V
Substitute the initial volume value:
- Work done (W) = -0.048 kcal * 16 kg
Calculate the final work done:
- Work done (W) = -0.768 kcal
Therefore, the work done during the process is approximately 0.768 kcal.
So, the closest option provided is 0.780 kcal.
- Initial mass of oxygen gas (m) = 16 kg
- Initial volume of oxygen gas (V1) = V
- Final volume of oxygen gas (V2) = 2V
- Initial pressure (P1) = 1 atm
- Final pressure (P2) = 1 atm (isobaric process)
Calculating work done:
- Work done (W) = -PΔV
- Where ΔV = V2 - V1 = V
Substitute the values:
- Work done (W) = -PΔV
- Work done (W) = -1 atm * V
Convert atm to Joules:
- 1 atm = 101.325 J
Substitute the value of atm in Joules:
- Work done (W) = -101.325 J * V
Convert Joules to kcal:
- 1 J = 0.000239 kcal
Substitute the value of Joules in kcal:
- Work done (W) = -101.325 J * V * 0.000239 kcal
Given final volume is double the initial volume:
- V2 = 2V
Substitute the value of V2 in terms of V:
- Work done (W) = -101.325 J * 2V * 0.000239 kcal
Simplify the expression:
- Work done (W) = -0.048 kcal * V
Substitute the initial volume value:
- Work done (W) = -0.048 kcal * 16 kg
Calculate the final work done:
- Work done (W) = -0.768 kcal
Therefore, the work done during the process is approximately 0.768 kcal.
So, the closest option provided is 0.780 kcal.
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16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal?
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16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal?.
16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16Kg oxygen gas expand at STP isobarically to occupy double of its original volume. The work done during the process is nearly a. 260kcal b. 180kcal c. 130kcal d. 271kcal?.
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