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An alternator of 300 kW is driven by a prime mover of speed regulation of 4% and another alternator of 200 kW is driven by a prime mover of speed regulation of 3%, when operating in parallel, the total load they can take without any of them being overloaded is -
- a)425 kW
- b)567 kW
- c)500 kW
- d)257 kW
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
An alternator of 300 kW is driven by a prime mover of speed regulation...
Concept:
The speed regulation of the alternator is given by:
where, SR = Speed regulation
NNL = No-load speed
NFL = Full load speed
Calculation:
Given, P1 = 300 kW
P2 = 200 kW
Let the load shared by two machines be x and y kW.
8x = 9y
Machine 2 produces less power than 1, so it will work at its rated condition.
8x = 9 × 200
x = 225 kW
P1 + P2 = 225 + 200
PT = 425 kW
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Community Answer
An alternator of 300 kW is driven by a prime mover of speed regulation...
Given:
- Power rating of one alternator = 300 kW
- Speed regulation of the prime mover driving the first alternator = 4%
- Power rating of the second alternator = 200 kW
- Speed regulation of the prime mover driving the second alternator = 3%
To find:
The total load they can take without any of them being overloaded.
Solution:
The speed regulation of a prime mover determines how much the prime mover's speed changes for a given change in load. It is typically expressed as a percentage of the prime mover's rated speed.
Step 1: Calculate the maximum power output of the first alternator without overloading it.
- Power rating of the first alternator = 300 kW
- Speed regulation of the prime mover driving the first alternator = 4%
- Maximum allowable change in speed = 4% of rated speed = 0.04 * rated speed
When the load on the first alternator increases, the prime mover's speed decreases. To avoid overloading the alternator, the decrease in speed should not exceed the maximum allowable change in speed.
Let's assume the rated speed of the prime mover is N rpm. The maximum allowable decrease in speed is 0.04 * N rpm.
The power output of the first alternator is proportional to the square of the speed. So, the maximum power output without overloading can be calculated as follows:
Maximum power output of the first alternator = (rated speed - maximum allowable decrease in speed)^2 * rated power
The rated power of the first alternator is 300 kW.
Step 2: Calculate the maximum power output of the second alternator without overloading it.
- Power rating of the second alternator = 200 kW
- Speed regulation of the prime mover driving the second alternator = 3%
- Maximum allowable change in speed = 3% of rated speed = 0.03 * rated speed
Using a similar approach as in Step 1, we can calculate the maximum power output of the second alternator without overloading it.
Maximum power output of the second alternator = (rated speed - maximum allowable decrease in speed)^2 * rated power
The rated power of the second alternator is 200 kW.
Step 3: Calculate the total load they can take without any of them being overloaded.
The total load they can take without any of them being overloaded is the sum of the maximum power outputs of both alternators.
Total load = Maximum power output of the first alternator + Maximum power output of the second alternator
Calculation:
Let's assume the rated speed of both prime movers is 1000 rpm for simplicity.
Step 1:
Maximum power output of the first alternator = (1000 - 0.04 * 1000)^2 * 300 kW = 960000 * 300 kW = 288000 kW
Step 2:
Maximum power output of the second alternator = (1000 - 0.03 * 1000)^2 * 200 kW = 970000 * 200 kW = 194000 kW
Step 3:
Total load = 288000 kW + 194000 kW = 482000 kW
Therefore, the total load they can take
- Power rating of one alternator = 300 kW
- Speed regulation of the prime mover driving the first alternator = 4%
- Power rating of the second alternator = 200 kW
- Speed regulation of the prime mover driving the second alternator = 3%
To find:
The total load they can take without any of them being overloaded.
Solution:
The speed regulation of a prime mover determines how much the prime mover's speed changes for a given change in load. It is typically expressed as a percentage of the prime mover's rated speed.
Step 1: Calculate the maximum power output of the first alternator without overloading it.
- Power rating of the first alternator = 300 kW
- Speed regulation of the prime mover driving the first alternator = 4%
- Maximum allowable change in speed = 4% of rated speed = 0.04 * rated speed
When the load on the first alternator increases, the prime mover's speed decreases. To avoid overloading the alternator, the decrease in speed should not exceed the maximum allowable change in speed.
Let's assume the rated speed of the prime mover is N rpm. The maximum allowable decrease in speed is 0.04 * N rpm.
The power output of the first alternator is proportional to the square of the speed. So, the maximum power output without overloading can be calculated as follows:
Maximum power output of the first alternator = (rated speed - maximum allowable decrease in speed)^2 * rated power
The rated power of the first alternator is 300 kW.
Step 2: Calculate the maximum power output of the second alternator without overloading it.
- Power rating of the second alternator = 200 kW
- Speed regulation of the prime mover driving the second alternator = 3%
- Maximum allowable change in speed = 3% of rated speed = 0.03 * rated speed
Using a similar approach as in Step 1, we can calculate the maximum power output of the second alternator without overloading it.
Maximum power output of the second alternator = (rated speed - maximum allowable decrease in speed)^2 * rated power
The rated power of the second alternator is 200 kW.
Step 3: Calculate the total load they can take without any of them being overloaded.
The total load they can take without any of them being overloaded is the sum of the maximum power outputs of both alternators.
Total load = Maximum power output of the first alternator + Maximum power output of the second alternator
Calculation:
Let's assume the rated speed of both prime movers is 1000 rpm for simplicity.
Step 1:
Maximum power output of the first alternator = (1000 - 0.04 * 1000)^2 * 300 kW = 960000 * 300 kW = 288000 kW
Step 2:
Maximum power output of the second alternator = (1000 - 0.03 * 1000)^2 * 200 kW = 970000 * 200 kW = 194000 kW
Step 3:
Total load = 288000 kW + 194000 kW = 482000 kW
Therefore, the total load they can take
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An alternator of 300 kW is driven by a prime mover of speed regulation of 4% and another alternator of 200 kW is driven by a prime mover of speed regulation of 3%, when operating in parallel, the total load they can take without any of them being overloaded is -a)425 kWb)567 kWc)500 kWd)257 kWCorrect answer is option 'A'. Can you explain this answer?
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An alternator of 300 kW is driven by a prime mover of speed regulation of 4% and another alternator of 200 kW is driven by a prime mover of speed regulation of 3%, when operating in parallel, the total load they can take without any of them being overloaded is -a)425 kWb)567 kWc)500 kWd)257 kWCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An alternator of 300 kW is driven by a prime mover of speed regulation of 4% and another alternator of 200 kW is driven by a prime mover of speed regulation of 3%, when operating in parallel, the total load they can take without any of them being overloaded is -a)425 kWb)567 kWc)500 kWd)257 kWCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alternator of 300 kW is driven by a prime mover of speed regulation of 4% and another alternator of 200 kW is driven by a prime mover of speed regulation of 3%, when operating in parallel, the total load they can take without any of them being overloaded is -a)425 kWb)567 kWc)500 kWd)257 kWCorrect answer is option 'A'. Can you explain this answer?.
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