Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A one-phase, 50 Hz, 40 kVA transformer with a...
Start Learning for Free
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.
- a)856.8 W
- b)214.2 W
- c)642.6 W
- d)428.4 W
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V ha...
Concept:
Consider a two winding single phase transformer as shown below,
N1 = primary winding turns
N2 = secondary winding turns
V1 = primary winding voltage
V2 = secondary winding voltage
I1 = current through the primary winding
I2 = current through the secondary winding
Transformation ratio: It is defined as the ratio of the secondary voltage to the primary voltage. It is denoted by K.
Transformer equivalent circuit with respect to secondary can be represented a show below
Where R02 = Effective resistance of the transformer as referred to the secondary side of the transformer.
R02 = R2 + R1' ------- (2)
R1' = Equivalent primary resistance as referred to the secondary winding
R1' = R1 × K 2 ------ (3)
Similarly, effective resistance of the transformer as referred to the primary side of the transformer is given as,
R01 = R1 + R2'
R2' = Equivalent secondary resistance as referred to the primary winding
R2' = R2 / K 2
Calculation:
Given data
V1 = 2000 V, V2 = 250 V, R1 = 1.15 Ω, R2 = 0.0155 Ω
From equation(1)
K= V2 / V1
K = 250 / 2000
K = 1 / 8
Effective resistance of the transformer as referred to the secondary of the transformer.
From equations(2) & (3)
R02 = 0.0155 + 1.15 / 82
R02 = 0.0335 Ω
Power output P = 40 kVA
V2 I2 = 40 × 103
I2 = 40000 / 250
I2 = 160 A = Ifl
Ifl is the full load current flowing through the secondary.
We required to find power loss at half full load condition
So, current at half full load is given as,
∴ Total power loss at half full load condition is given as,
Phfl = I2hfl × R02
Phfl = 802 × 0.0335
Phfl = 214.2 W
Free Test
FREE
| Start Free Test |
Community Answer
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V ha...
Calculation of Total Copper Loss on Half of Full Load:
Given Data:
- Power rating of the transformer (S) = 40 kVA
- Voltage ratio (V1/V2) = 2000 V/250 V
- Primary resistance (R1) = 1.15 Ω
- Secondary resistance (R2) = 0.0155 Ω
Formula for Copper Loss:
- Copper loss = I^2 * R
Calculations:
1. Calculate the full load current (I2):
- S = V2 * I2
- 40 kVA = 250 V * I2
- I2 = 40,000 VA / 250 V = 160 A
2. Calculate the current on half of full load:
- I_half = I2 / 2 = 160 A / 2 = 80 A
3. Calculate the voltage on primary side (V1):
- V1 = V2 * (V1/V2) = 250 V * (2000/250) = 2000 V
4. Calculate the current on primary side (I1):
- I1 = S / V1 = 40,000 VA / 2000 V = 20 A
5. Calculate the total resistance (R_total) on primary side:
- R_total = R1 + (V1/V2)^2 * R2
- R_total = 1.15 Ω + (2000/250)^2 * 0.0155 Ω
- R_total = 1.15 Ω + 400 * 0.0155 Ω
- R_total = 1.15 Ω + 6.2 Ω = 7.35 Ω
6. Calculate the total copper loss on half of full load:
- Copper loss = (I1)^2 * R_total
- Copper loss = (20 A)^2 * 7.35 Ω
- Copper loss = 400 * 7.35 W
- Copper loss = 2940 W
Therefore, the total copper loss on half of full load is 2940 W or 2940/2 = 1470 W
The closest option to the calculated value is 214.2 W, which is the correct answer.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer?
Question Description
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer?.
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A one-phase, 50 Hz, 40 kVA transformer with a ratio of 2000 V/250 V has a primary resistance of 1.15 Ω and a secondary resistance of 0.0155 Ω. Calculate total copper loss on half of the full load.a)856.8 Wb)214.2 Wc)642.6 Wd)428.4 WCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup