Balancing the Equation:

To balance the given equation, we need to ensure that the number of atoms on both sides of the equation is the same. Let's start by balancing the chromium (Cr) atoms:

a) When a=2, we have 2 Cr on the left side. To balance this, we need 2 Cr on the right side as well. So, x=2.

Next, let's balance the oxygen (O) atoms:

a) When a=2, we have 14 O atoms on the left side (2 from K2Cr2O7 and 12 from H2SO4). To balance this, we need 14 O atoms on the right side as well. Since each CrO2Cl2 molecule contains 7 O atoms, x=2 implies 14 O atoms on the right side.

Now, let's balance the chlorine (Cl) atoms:

a) When b=4, we have 4 Cl atoms on the right side. Since each CrO2Cl2 molecule contains 2 Cl atoms, x=2 implies 4 Cl atoms on the right side.

Finally, let's balance the hydrogen (H) and sulfur (S) atoms:

a) When c=6, we have 6 H atoms on the left side. To balance this, we need 6 H atoms on the right side as well. Since each KHSO4 molecule contains 1 H atom, y=6.

a) When c=6, we have 6 S atoms on the left side. To balance this, we need 6 S atoms on the right side as well. Since each H2SO4 molecule contains 1 S atom, z=6.

The balanced equation is:

2 K2Cr2O7 + 4 KCl + 6 H2SO4 → 2 CrO2Cl2 + 6 KHSO4 + 3 H2O

Explanation:

The given equation involves the reaction between potassium dichromate (K2Cr2O7), potassium chloride (KCl), and sulfuric acid (H2SO4), resulting in the formation of chromium(IV) oxide chloride (CrO2Cl2), potassium bisulfate (KHSO4), and water (H2O).

To balance the equation, we first determine the number of atoms of each element on both sides. Then, we adjust the coefficients of the compounds to ensure the same number of atoms on both sides.

In this case, we started by balancing the chromium (Cr) atoms. Since there are 2 Cr atoms on the left side, we need 2 Cr atoms on the right side as well, which is achieved by setting x=2.

Next, we balanced the oxygen (O) atoms. With a=2, there are 14 O atoms on the left side. To balance this, we set x=2, as each CrO2Cl2 molecule contributes 7 O atoms.

The chlorine (Cl) atoms are balanced by setting x=2, as each CrO2Cl2 molecule contains 2 Cl atoms.

Finally, we balanced the hydrogen (H) and sulfur (S) atoms. With c=6, there are 6 H and 6 S atoms on the left side. These are balanced by setting y=6 and z=6, as each KHSO4 molecule contains 1 H and 1 S atom.

The final balanced

B){1} K2Cr2O7 + {4}KCl + {6}H2SO4 ==> {2}CrO2Cl2 + {6}KHSO4 + {3}H2Obalance all atom on both side......here u have option u can try by putting values given in option....