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A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)?
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A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has un...
Given:
Length of the cylindrical magnetic rod, l = 5 cm
Diameter of the cylindrical magnetic rod, d = 1 cm
Uniform magnetization, M = 5.3 × 10^3 Am^(-1)
To find:
The net magnetic dipole moment of the rod
Solution:
The magnetic dipole moment is given by the formula:
Magnetic dipole moment (m) = M * V
where M is the magnetization and V is the volume of the magnet.
1. Calculating the volume of the magnet
The cylindrical rod can be considered as a cylinder. The volume of a cylinder is given by the formula:
Volume (V) = π * r^2 * h
where r is the radius of the cylinder and h is the height of the cylinder.
Given that the diameter of the rod is 1 cm, the radius (r) can be calculated as:
r = d/2 = 1/2 = 0.5 cm = 0.005 m
The height (h) of the rod is given as 5 cm = 0.05 m
Substituting the values into the formula, we get:
V = π * (0.005)^2 * 0.05
2. Calculating the magnetic dipole moment
The magnetic dipole moment is given by the formula:
m = M * V
Substituting the values of M and V, we get:
m = 5.3 × 10^3 Am^(-1) * π * (0.005)^2 * 0.05
Simplifying the equation:
m = 5.3 × 10^3 * π * (0.000025) * 0.05
m = 5.3 × 10^3 * π * 0.00000125
m = 5.3 × 10^3 * 3.14 * 0.00000125
m = 0.020765
Therefore, the net magnetic dipole moment of the cylindrical magnetic rod is approximately 0.020765 A.
The correct option is A) 10^(-2) * J * T^(-1)
Length of the cylindrical magnetic rod, l = 5 cm
Diameter of the cylindrical magnetic rod, d = 1 cm
Uniform magnetization, M = 5.3 × 10^3 Am^(-1)
To find:
The net magnetic dipole moment of the rod
Solution:
The magnetic dipole moment is given by the formula:
Magnetic dipole moment (m) = M * V
where M is the magnetization and V is the volume of the magnet.
1. Calculating the volume of the magnet
The cylindrical rod can be considered as a cylinder. The volume of a cylinder is given by the formula:
Volume (V) = π * r^2 * h
where r is the radius of the cylinder and h is the height of the cylinder.
Given that the diameter of the rod is 1 cm, the radius (r) can be calculated as:
r = d/2 = 1/2 = 0.5 cm = 0.005 m
The height (h) of the rod is given as 5 cm = 0.05 m
Substituting the values into the formula, we get:
V = π * (0.005)^2 * 0.05
2. Calculating the magnetic dipole moment
The magnetic dipole moment is given by the formula:
m = M * V
Substituting the values of M and V, we get:
m = 5.3 × 10^3 Am^(-1) * π * (0.005)^2 * 0.05
Simplifying the equation:
m = 5.3 × 10^3 * π * (0.000025) * 0.05
m = 5.3 × 10^3 * π * 0.00000125
m = 5.3 × 10^3 * 3.14 * 0.00000125
m = 0.020765
Therefore, the net magnetic dipole moment of the cylindrical magnetic rod is approximately 0.020765 A.
The correct option is A) 10^(-2) * J * T^(-1)
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A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)?
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A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)?.
A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical magnetic rod has length5 cm and diameter 1 cm. It has uniformmagnetization 5.3 × 103 Am¹ Its net magnetic dipole moment nearly(Pi = 22/7) A)10 ^ - 2 * J * T ^ - 1 B) 0.5 * 10 ^ - 2 * sqrt^- 1 T C)2.5 * 10 ^ - 2 * sqrt(T ^ - 1) D) 2.5 * 10 ^ - 2 * sqrt(T ^ - 1)?.
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