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The lowest alkene which is capable of exhibiting geometrical isomerism is
- a)1-butene
- b)2-pentene
- c)2-butene Correct Answer.
- d)2,3-dimethylbutene
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The lowest alkene which is capable of exhibiting geometrical isomerism...
Understanding Geometrical Isomerism
Geometrical isomerism, also known as cis-trans isomerism, occurs in alkenes when there is restricted rotation around the double bond and when each carbon in the double bond has different substituents.
Why 2-Butene Exhibits Geometrical Isomerism
- Structure of 2-butene:
- The molecular formula is C₄H₈.
- It has a double bond between the second and third carbon atoms (C=C).
- Substituents on the double bond:
- The two carbon atoms involved in the double bond (C2 and C3) each have different groups attached.
- For example, in cis-2-butene, the two methyl groups (CH₃) are on the same side, while in trans-2-butene, they are on opposite sides.
Other Options Explained
- 1-Butene (Option A):
- It has the structure CH₂=CH-CH₂-CH₃.
- Both carbons involved in the double bond have the same hydrogen substituents, meaning it cannot exhibit geometrical isomerism.
- 2-Pentene (Option B):
- This can exhibit geometrical isomerism; however, it is not the lowest alkene with such capability.
- 2,3-Dimethylbutene (Option D):
- While this compound can exhibit isomerism, it is a higher alkene compared to 2-butene.
Conclusion
Thus, the lowest alkene capable of exhibiting geometrical isomerism is 2-butene (Option C), as it meets the criteria for having different substituents on the double bond while being the simplest form that can do so.
Geometrical isomerism, also known as cis-trans isomerism, occurs in alkenes when there is restricted rotation around the double bond and when each carbon in the double bond has different substituents.
Why 2-Butene Exhibits Geometrical Isomerism
- Structure of 2-butene:
- The molecular formula is C₄H₈.
- It has a double bond between the second and third carbon atoms (C=C).
- Substituents on the double bond:
- The two carbon atoms involved in the double bond (C2 and C3) each have different groups attached.
- For example, in cis-2-butene, the two methyl groups (CH₃) are on the same side, while in trans-2-butene, they are on opposite sides.
Other Options Explained
- 1-Butene (Option A):
- It has the structure CH₂=CH-CH₂-CH₃.
- Both carbons involved in the double bond have the same hydrogen substituents, meaning it cannot exhibit geometrical isomerism.
- 2-Pentene (Option B):
- This can exhibit geometrical isomerism; however, it is not the lowest alkene with such capability.
- 2,3-Dimethylbutene (Option D):
- While this compound can exhibit isomerism, it is a higher alkene compared to 2-butene.
Conclusion
Thus, the lowest alkene capable of exhibiting geometrical isomerism is 2-butene (Option C), as it meets the criteria for having different substituents on the double bond while being the simplest form that can do so.
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Community Answer
The lowest alkene which is capable of exhibiting geometrical isomerism...
Alkenes exhibit geometrical isomerism due to restricted rotation around the caron-carbon double bond. However, the alkene molecule should not have the same groups attached to the double bonded carbon atom.
Hence, but-2-ene (CH3CH=CHCH3) is the smallest alkene to exhibit geometrical isomerism.
Hence, but-2-ene (CH3CH=CHCH3) is the smallest alkene to exhibit geometrical isomerism.
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The lowest alkene which is capable of exhibiting geometrical isomerism isa)1-buteneb)2-pentenec)2-butene Correct Answer.d)2,3-dimethylbuteneCorrect answer is option 'C'. Can you explain this answer?
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