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Particle follows a path XY as shown in the given figure. If the radius of semi-circular path
is 2 cm then the approximate value of distance covered and displacement of the particle
are respectively?
is 2 cm then the approximate value of distance covered and displacement of the particle
are respectively?
Most Upvoted Answer
Particle follows a path XY as shown in the given figure. If the radius...
Path of the Particle
The given figure shows the path of a particle, which consists of a semi-circular path with a radius of 2 cm.
Distance Covered by the Particle
To calculate the distance covered by the particle, we need to find the length of the curved path. The length of a semi-circular path can be calculated using the formula:
Length = π * radius
In this case, the radius is given as 2 cm, so the length of the curved path is:
Length = π * 2 cm
Using the approximate value of π as 3.14, we can calculate:
Length = 3.14 * 2 cm
= 6.28 cm
Therefore, the distance covered by the particle is approximately 6.28 cm.
Displacement of the Particle
The displacement of a particle is the shortest distance between its initial and final positions, measured along a straight line. In this case, the particle starts at point X and ends at point Y.
To find the displacement, we can draw a straight line connecting points X and Y. The length of this line will give us the displacement.
The distance between X and Y can be calculated using the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the straight line connecting points X and Y is the hypotenuse of a right-angled triangle, with the radius of the semi-circular path as one side and the length of the curved path as the other side.
Using the formula for the length of the hypotenuse of a right-angled triangle, we can calculate the displacement:
Displacement = √(length of curved path)^2 + (radius)^2
Substituting the values, we get:
Displacement = √(6.28 cm)^2 + (2 cm)^2
= √(39.38 cm^2 + 4 cm^2)
= √43.38 cm^2
≈ 6.59 cm
Therefore, the displacement of the particle is approximately 6.59 cm.
Summary
- The distance covered by the particle is approximately 6.28 cm, which is the length of the curved path.
- The displacement of the particle is approximately 6.59 cm, which is the shortest distance between its initial and final positions.
The given figure shows the path of a particle, which consists of a semi-circular path with a radius of 2 cm.
Distance Covered by the Particle
To calculate the distance covered by the particle, we need to find the length of the curved path. The length of a semi-circular path can be calculated using the formula:
Length = π * radius
In this case, the radius is given as 2 cm, so the length of the curved path is:
Length = π * 2 cm
Using the approximate value of π as 3.14, we can calculate:
Length = 3.14 * 2 cm
= 6.28 cm
Therefore, the distance covered by the particle is approximately 6.28 cm.
Displacement of the Particle
The displacement of a particle is the shortest distance between its initial and final positions, measured along a straight line. In this case, the particle starts at point X and ends at point Y.
To find the displacement, we can draw a straight line connecting points X and Y. The length of this line will give us the displacement.
The distance between X and Y can be calculated using the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the straight line connecting points X and Y is the hypotenuse of a right-angled triangle, with the radius of the semi-circular path as one side and the length of the curved path as the other side.
Using the formula for the length of the hypotenuse of a right-angled triangle, we can calculate the displacement:
Displacement = √(length of curved path)^2 + (radius)^2
Substituting the values, we get:
Displacement = √(6.28 cm)^2 + (2 cm)^2
= √(39.38 cm^2 + 4 cm^2)
= √43.38 cm^2
≈ 6.59 cm
Therefore, the displacement of the particle is approximately 6.59 cm.
Summary
- The distance covered by the particle is approximately 6.28 cm, which is the length of the curved path.
- The displacement of the particle is approximately 6.59 cm, which is the shortest distance between its initial and final positions.
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Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively?
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Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively?.
Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Particle follows a path XY as shown in the given figure. If the radius of semi-circular pathis 2 cm then the approximate value of distance covered and displacement of the particleare respectively?.
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