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In a dihybrid cross pure red pollen pea plant was crossed with short pollen pea plant If linkage is 66% then calculate no. Of white long pollen plant among total progeny of 1000. Please explain with solution. .?
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In a dihybrid cross pure red pollen pea plant was crossed with short p...
Given the linkage between the two genes = 66%.Hence, the parental type i.e pure red-long pollen pea plants and white-short pollen pea plants will be = 66% of 1000 = 660 pea plants. Among, the 660 parental type 330 plants will be red-long pollen pea plant and 330 will be white-short pollen pea approximately taking them equal.Now, number of recombinant type pea plants i.e white-long pollen pea plants and Red-short pollen pea plants will be = 1000 - 660 = 340. Taking white-long pollen pea plants and Red-short pollen pea plants equal.Therefore, the number of white-long pollen pea plants will be = 340/2 = 170 plants.
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In a dihybrid cross pure red pollen pea plant was crossed with short p...

Solution:

Given information:
- Dihybrid cross between pure red (RR) and short (ss) pollen pea plants
- Linkage is 66%

Calculations:
- Since there is linkage, the two genes are located close together on the same chromosome.
- The percentage of recombination is 100% - 66% = 34%

Recombination frequency:
- The recombination frequency between the two genes is 34%, which means 34% of the offspring will show a different combination of traits compared to the parent plants.

Calculating number of white long pollen plants:
- Since we are given 34% recombination, we can calculate the total number of white long pollen plants among 1000 progeny.
- 34% of 1000 progeny = 0.34 x 1000 = 340 white long pollen plants

Therefore, among the total progeny of 1000, there will be 340 white long pollen plants.
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In a dihybrid cross pure red pollen pea plant was crossed with short p...
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In a dihybrid cross pure red pollen pea plant was crossed with short pollen pea plant If linkage is 66% then calculate no. Of white long pollen plant among total progeny of 1000. Please explain with solution. .?
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