Can you explain the answer of this question below:The decrease of resi...
Resistance (R)depends on the resistivity of the nuteial (pl. length of the oats' (Li and cross sectional area (A) of the material following the equation:
R = p* L/A
When hooking resistors in parallel, you are increasingthecross sectional area of the resistance path. If you like to use the water hose analogy, you are draining the tub (battery - power source)with two hoses (resistors)instead of one. It makes the tub move water (current) Faster because you have more paths (bigger cross sectional area) for the water to flow.
If you look at the original equation above you will notice that replacing A with 2A (two of the same resistors in parade) you will cut the resistance in half.
That's the theory. In practice. to find the resistance you would Ix/mayjust add the reciprocal ol the usevidual resistors to get the reciprocal of the total resistance
1/R -total = 1/RI + 1/R2 + 1/R3 + ....
for however many resistors you have in parallel. For example.
If you have only 2 resistors in parallel. a 50 ohm in parallel with a 100 ohm resistor then...
1/R - total = 1 /50 ohm + 1/100 ohm = 2/100 ohm + 1/100 ohm
= 3/100 ohm
so,
R - total = 103/3 = 33.3 ohm (most peocre forget die step)
A good rule to remember is that you total resistance is less than the smallest resistor when they are connected in parallel.