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Can you explain the answer of this question below:
What is the angle in degrees made by a sector, the ratio of whose area with the area of the semicircle is equal to 1:10?
  • A:
    36
  • B:
    18
  • C:
    24
  • D:
    9
The answer is b.
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Can you explain the answer of this question below:What is the angle in...
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Can you explain the answer of this question below:What is the angle in...
To solve this problem, we need to understand the relationship between the area of a sector and the area of a semicircle.

The area of a sector is given by the formula:
Area of sector = (θ/360) * π * r^2

The area of a semicircle is given by the formula:
Area of semicircle = (1/2) * π * r^2

Given that the ratio of the area of the sector to the area of the semicircle is 1:10, we can set up the following equation:

(θ/360) * π * r^2 / ((1/2) * π * r^2) = 1/10

Simplifying this equation, we can cancel out the common terms:

(θ/360) / (1/2) = 1/10

Now, cross-multiply:

(θ/360) * 2 = 1/10

θ/180 = 1/10

Multiply both sides of the equation by 180:

θ = 18

Therefore, the angle in degrees made by the sector is 18 degrees.

Hence, the correct answer is option B (18).
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Can you explain the answer of this question below:What is the angle in...
The angle made by semi-circle is 180 degrees and the angle suspended by the sector will be in same ratio as areas. area of semi circle πR^2 area of sector πR^2/10 so angle suspended will be 180/10=18
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Can you explain the answer of this question below:What is the angle in degrees made by a sector, the ratio of whose area with the area of the semicircle is equal to 1:10?A:36B:18C:24D:9The answer is b.
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