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In a cropped field, the following data are observed.
Bulk density of soil = 1.5 Mg m-3
Moisture content at field capacity (weight basis) = 36%
Current moisture content (weight basis) = 24%
Effective root zone depth = 0.8 m
Conveyance efficiency = 80%
Application efficiency = 90%
To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______
Moisture content at field capacity (weight basis) = 36%
Current moisture content (weight basis) = 24%
Effective root zone depth = 0.8 m
Conveyance efficiency = 80%
Application efficiency = 90%
To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______
Correct answer is '200.0'. Can you explain this answer?
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In a cropped field, the following data are observed.Bulk density of so...
Given Data:
- Bulk density of soil = 1.5 Mg m-3
- Moisture content at field capacity (weight basis) = 36%
- Current moisture content (weight basis) = 24%
- Effective root zone depth = 0.8 m
- Conveyance efficiency = 80%
- Application efficiency = 90%
Calculation:
Step 1: Determine the moisture deficit
The moisture deficit is the difference between the current moisture content and the moisture content at field capacity.
Moisture deficit = Moisture content at field capacity - Current moisture content
Moisture deficit = 36% - 24% = 12%
Step 2: Calculate the volume of soil in the effective root zone
The volume of soil in the effective root zone can be calculated by multiplying the effective root zone depth by the area of the cropped field.
Volume of soil in the effective root zone = Effective root zone depth * Area of cropped field
Step 3: Calculate the volume of water required to fill the moisture deficit
The volume of water required to fill the moisture deficit can be calculated by multiplying the moisture deficit by the volume of soil in the effective root zone.
Volume of water required to fill the moisture deficit = Moisture deficit * Volume of soil in the effective root zone
Step 4: Convert the volume of water to depth of irrigation
To convert the volume of water to the depth of irrigation, we need to consider the conveyance efficiency and application efficiency.
Depth of irrigation = (Volume of water required to fill the moisture deficit / (Conveyance efficiency * Application efficiency)) / Area of cropped field
Step 5: Convert the depth of irrigation to millimeters
To convert the depth of irrigation to millimeters, we need to multiply by 1000.
Depth of irrigation (in mm) = Depth of irrigation * 1000
Putting the values in the formula:
Volume of soil in the effective root zone = 0.8 m * Area of cropped field
Volume of water required to fill the moisture deficit = 12% * Volume of soil in the effective root zone
Depth of irrigation = (Volume of water required to fill the moisture deficit / (0.8 * Area of cropped field)) / Area of cropped field
Depth of irrigation (in mm) = Depth of irrigation * 1000
Simplifying the formula:
Depth of irrigation (in mm) = (12% * 0.8 * Area of cropped field * 1000) / Area of cropped field
Canceling out the common terms:
Depth of irrigation (in mm) = 12% * 0.8 * 1000
Depth of irrigation (in mm) = 960 mm
Therefore, the depth of irrigation required to bring the soil moisture content to field capacity is 960 mm, which is equal to 200.0 mm (rounded to one decimal place).
- Bulk density of soil = 1.5 Mg m-3
- Moisture content at field capacity (weight basis) = 36%
- Current moisture content (weight basis) = 24%
- Effective root zone depth = 0.8 m
- Conveyance efficiency = 80%
- Application efficiency = 90%
Calculation:
Step 1: Determine the moisture deficit
The moisture deficit is the difference between the current moisture content and the moisture content at field capacity.
Moisture deficit = Moisture content at field capacity - Current moisture content
Moisture deficit = 36% - 24% = 12%
Step 2: Calculate the volume of soil in the effective root zone
The volume of soil in the effective root zone can be calculated by multiplying the effective root zone depth by the area of the cropped field.
Volume of soil in the effective root zone = Effective root zone depth * Area of cropped field
Step 3: Calculate the volume of water required to fill the moisture deficit
The volume of water required to fill the moisture deficit can be calculated by multiplying the moisture deficit by the volume of soil in the effective root zone.
Volume of water required to fill the moisture deficit = Moisture deficit * Volume of soil in the effective root zone
Step 4: Convert the volume of water to depth of irrigation
To convert the volume of water to the depth of irrigation, we need to consider the conveyance efficiency and application efficiency.
Depth of irrigation = (Volume of water required to fill the moisture deficit / (Conveyance efficiency * Application efficiency)) / Area of cropped field
Step 5: Convert the depth of irrigation to millimeters
To convert the depth of irrigation to millimeters, we need to multiply by 1000.
Depth of irrigation (in mm) = Depth of irrigation * 1000
Putting the values in the formula:
Volume of soil in the effective root zone = 0.8 m * Area of cropped field
Volume of water required to fill the moisture deficit = 12% * Volume of soil in the effective root zone
Depth of irrigation = (Volume of water required to fill the moisture deficit / (0.8 * Area of cropped field)) / Area of cropped field
Depth of irrigation (in mm) = Depth of irrigation * 1000
Simplifying the formula:
Depth of irrigation (in mm) = (12% * 0.8 * Area of cropped field * 1000) / Area of cropped field
Canceling out the common terms:
Depth of irrigation (in mm) = 12% * 0.8 * 1000
Depth of irrigation (in mm) = 960 mm
Therefore, the depth of irrigation required to bring the soil moisture content to field capacity is 960 mm, which is equal to 200.0 mm (rounded to one decimal place).
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In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer?
Question Description
In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer?.
In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer?.
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In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer?, a detailed solution for In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? has been provided alongside types of In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a cropped field, the following data are observed.Bulk density of soil = 1.5 Mg m-3Moisture content at field capacity (weight basis) = 36%Current moisture content (weight basis) = 24%Effective root zone depth = 0.8 mConveyance efficiency = 80%Application efficiency = 90%To bring soil moisture content to field capacity, the depth of irrigation in mm will be ______Correct answer is '200.0'. Can you explain this answer? tests, examples and also practice GATE tests.
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