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In a single throw of a die, the probability of getting a multiple of 3 is


  • A:
    1/6

  • B:
    1/3

  • C:
    3/6

  • D:
    4/6

The answer is B.
Verified Answer
In a single throw of a die, the probability of getting a multiple of 3...
Given : A die is thrown once .
A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6
Number of possible outcomes are = 6
Let E = Event of getting a getting a multiple of 3
Multiples of 3 are = 3, 6
Number of outcome favourable to E = 2
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 2/6  = 1/3
Hence, the probability of getting a  multiple of 3, P(E) = 1/3
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Most Upvoted Answer
In a single throw of a die, the probability of getting a multiple of 3...
Just make sets of 3 numbers 1,2,3,4,5,6,7,8,9,... Means 1,2,3 4,5,6 7,8,9 In every set you will find only single number which is divisible by 3 In 1,2,3 3 is the number In 4,5,6 6 is the number In 7,8,9 9 is the number Likewise therefore, set contains total of 3 numbers but event is only 1. P(3) = 1/3.
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Community Answer
In a single throw of a die, the probability of getting a multiple of 3...
B
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In a single throw of a die, the probability of getting a multiple of 3 isA:1/6B:1/3C:3/6D:4/6The answer is B.
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