A face of the clock is divided into three parts. First part hours tota...
the clock normally has 12 hr
three parts x,y,z
x+y+z=12
x=y+z
2x=12
x=6
so the largest part is 6 hrs
View all questions of this testA face of the clock is divided into three parts. First part hours tota...
the clock normally has 12 hr
three parts x,y,z
x+y+z=12
x=y+z
2x=12
x=6
so the largest part is 6 hrs
A face of the clock is divided into three parts. First part hours tota...
Explanation:
The face of the clock is divided into three parts: the first part, the second part, and the third part. The first part represents the hours on the clock.
Given Information:
- Total hours in the first part = Total hours in the second part + Total hours in the third part
Let's solve the problem step by step:
Step 1: Assume that the total hours in the first part is x.
Step 2: Let's say the total hours in the second part is y and the total hours in the third part is z.
Step 3: According to the given information:
x = y + z
Step 4: Since there are 12 hours on a clock face, we have:
x + y + z = 12
Step 5: Substitute the value of x from Step 3 into Step 4:
y + z + y + z = 12
2y + 2z = 12
y + z = 6
Step 6: Therefore, the total hours in the bigger part (the first part) is 6.
So, the total hours in the bigger part (first part) of the clock face is 6.