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The de bronglie wavelengths of a neutron at 300K is lambda What will be wavelengths at 1200K .please answer with solution?
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The de bronglie wavelengths of a neutron at 300K is lambda What will b...
Lambda neutron is directly proportional to 1/√T... lambda1÷lambda2=root of temp2÷temp1 lambda1÷lambda2=root of 1200÷300 lambda÷lambda2=root of 4 (√4=2) lambda2=lambda÷2... hope u clear...!!😊
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The de bronglie wavelengths of a neutron at 300K is lambda What will b...
Lambda/2..!! 😊
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The de bronglie wavelengths of a neutron at 300K is lambda What will be wavelengths at 1200K .please answer with solution?
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