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Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:
- a)Recrystallisation
- b)Sublimation
- c)Fractional distillation
- d)Steam distillation
Correct answer is option 'A'. Can you explain this answer?
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Compounds (A) and (B) are soluble in water near to its boiling point. ...
Recrystallisation:
Recrystallisation is the method used to separate compounds (A) and (B) from their mixture based on differences in their solubility in a solvent. In this case, both compounds are soluble in water near its boiling point, but they have different solubilities.
Principle:
- The principle behind recrystallisation is that a compound with lower solubility will crystallize out of the solution first when the solution is cooled.
Process:
1. Dissolve the mixture of compounds (A) and (B) in hot water.
2. Filter the hot solution to remove any insoluble impurities.
3. Allow the solution to cool slowly. Compound (A), which has lower solubility, will start to crystallize out first.
4. Filter the solution again to separate the crystals of compound (A) from the remaining solution.
5. Wash the crystals of compound (A) with cold water to remove any impurities.
6. Dry the crystals to obtain pure compound (A).
7. The remaining solution will contain compound (B) in solution form.
Conclusion:
Recrystallisation is an effective method for separating compounds based on differences in solubility. In this case, compounds (A) and (B) can be separated using recrystallisation due to their different solubilities in water. This method allows for the isolation of pure compounds from a mixture.
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Compounds (A) and (B) are soluble in water near to its boiling point. ...
Since the solubilities of A and B are quite different, the technique of recrystallisation can be used to separate A and B from their mixture.
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Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer?
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Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer?.
Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Compounds (A) and (B) are soluble in water near to its boiling point. If the solubility of (A) is 2 g per 100 ml of water and the solubility of (B) is 4 g per 100 ml, then the name of method to separate (A) and (B) from their mixture is:a)Recrystallisationb)Sublimationc)Fractional distillationd)Steam distillationCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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