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The atomic numbers of vanadium (V), chromium (Cr), iron (Fe) and cobalt (Co) are 23, 24, 26 and 27, 
respectively
. Which one of these may be expected to have the highest second ionisation enthalpy?
  • a)
    V
  • b)
    Cr
  • c)
    Co
  • d)
    Fe
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The atomic numbers of vanadium (V), chromium (Cr), iron (Fe) and cobal...
Electronic configuration of Cr is:

So, due to half filled orbital I.P. is high of Cr.
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Community Answer
The atomic numbers of vanadium (V), chromium (Cr), iron (Fe) and cobal...

Explanation:

Second ionisation enthalpy:
- The second ionization energy is the energy required to remove the second outermost electron from a neutral atom.
- It is generally higher than the first ionization energy as removing an electron from a positively charged ion is more difficult.

Comparison:
- Chromium (Cr) has the highest second ionization enthalpy among vanadium (V), chromium (Cr), iron (Fe), and cobalt (Co).
- Chromium (Cr) has an electronic configuration of [Ar] 3d5 4s1.
- Removing an electron from a half-filled d orbital in chromium is more difficult compared to the other elements.
- Therefore, chromium (Cr) is expected to have the highest second ionization enthalpy.
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The atomic numbers of vanadium (V), chromium (Cr), iron (Fe) and cobalt (Co)are 23, 24, 26 and 27,respectively. Which one of these may be expected to have the highest second ionisation enthalpy?a)Vb)Crc)Cod)FeCorrect answer is option 'B'. Can you explain this answer?
Question Description
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