10 years ago the age of father was 4 times his son. 10 years hence the...
Given Information:
- 10 years ago, the age of the father was 4 times that of his son.
- 10 years from now, the age of the father will be twice that of his son.
Let's represent the ages of the father and son:
- Let the current age of the father be F and the current age of the son be S.
Forming Equations:
- From the given information, we can form two equations:
1. (F - 10) = 4(S - 10) [10 years ago, the age of the father was 4 times his son]
2. (F + 10) = 2(S + 10) [10 years hence, the age of the father will be twice that of his son]
Solving the Equations:
- By solving the above equations, we get:
1. F = 4S - 30
2. F = 2S + 10
- Equating the two equations for F, we get:
4S - 30 = 2S + 10
2S = 40
S = 20
- Substituting the value of S back into one of the equations, we get:
F = 2(20) + 10
F = 50
Calculating the Percentage:
- The percentage of the father's age compared to the total age (father + son) is:
Father's age percentage = (50 / (50 + 20)) * 100 = 71.43%
- The percentage of the son's age compared to the total age is:
Son's age percentage = (20 / (50 + 20)) * 100 = 28.57%
Conclusion:
- The father's age is 50 years, which is 71.43% of the total age, and the son's age is 20 years, which is 28.57% of the total age.