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A man age is three times the sum of AGS of his two son after 5 years his age will be twice th e sum of edges his to sons the?
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A man age is three times the sum of AGS of his two son after 5 years h...
Given Information:
- Let the man's current age be M and his two sons' ages be A and B.
- It is given that M = 3(A + B) and M + 5 = 2(A + 5 + B + 5).

Calculating the Current Ages:
- From the first equation, we get M = 3A + 3B.
- Substituting this value of M in the second equation, we get 3A + 3B + 5 = 2(A + B + 10).
- Simplifying, we get 3A + 3B + 5 = 2A + 2B + 20.
- Rearranging terms, we get A + B = 15.

Calculating the Man's Age:
- Substituting the value of A + B = 15 in the first equation, we get M = 3(15) = 45.

Calculating the Sons' Ages:
- Since A + B = 15, we can divide this equally between the two sons.
- Therefore, each son's current age is 15/2 = 7.5 years.

Verifying the Future Ages:
- In 5 years, the man's age will be 45 + 5 = 50.
- The sum of the sons' ages in 5 years will be 2*(7.5 + 5) = 25.

Conclusion:
- As calculated, after 5 years, the man's age will indeed be twice the sum of his two sons' ages.
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A man age is three times the sum of AGS of his two son after 5 years his age will be twice th e sum of edges his to sons the?
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