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Amilkman professes to sell milk at its CP only. But still he is making a profit of 20% since he has mixed some amount of water in the milk. What is the percentage of milk in the mixture?
  • a)
    80%
  • b)
    83.33%
  • c)
    75%
  • d)
    66.66%
Correct answer is 'B'. Can you explain this answer?
Verified Answer
Amilkman professes to sell milk at its CP only. But still he is making...
Alternatively, if he has initially 10 L of milk, he must have made it 12 L of mixture to get a profit of 20% (since SP per litre = CP per litre). Hence out of 12 litres of mixture, 10 litres is milk and 2 litres is water.
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Amilkman professes to sell milk at its CP only. But still he is making...
Milk sold at cp, so whatever the profit is because of water only, 20% profit means 1/5 , means water to milk ratio is 1:5 so that milk % = 5/6 = 83.33%
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Amilkman professes to sell milk at its CP only. But still he is making...
Solution:

Let's assume that the milkman has 1 liter of milk.

According to the question, the milkman sells the milk at its CP only, which means he sells 1 liter of milk at its cost price.

But the milkman adds some water to the milk to make a profit of 20%.

Let's assume that he adds 'x' liters of water to 1 liter of milk.

So, the total quantity of milk and water mixture becomes (1+x) liters.

Profit Percentage = (Profit/Cost Price) x 100

We know that the milkman is making a profit of 20%.

So, Profit Percentage = (Profit/Cost Price) x 100 = 20%

Cost Price = Selling Price - Profit

As the milkman is selling the milk at its CP, Selling Price = Cost Price.

So, Cost Price - Profit = Cost Price

Profit = 0.2 x Cost Price

Substituting the value of Profit in the above equation, we get

Cost Price - 0.2 x Cost Price = Cost Price

0.2 x Cost Price = x

x/Cost Price = 0.2

x = 0.2 x Cost Price

We know that the total quantity of mixture is (1+x) liters.

So, the quantity of milk in the mixture is 1 liter.

Percentage of Milk in the Mixture = (Quantity of Milk/Total Quantity of Mixture) x 100

Percentage of Milk in the Mixture = (1/(1+x)) x 100

Substituting the value of x in the above equation, we get

Percentage of Milk in the Mixture = (1/(1+0.2 x Cost Price)) x 100

Percentage of Milk in the Mixture = (1/(1+0.2)) x 100

Percentage of Milk in the Mixture = (1/1.2) x 100

Percentage of Milk in the Mixture = 83.33%

Therefore, the percentage of milk in the mixture is 83.33%.
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Amilkman professes to sell milk at its CP only. But still he is making a profit of 20% since he has mixed some amount of water in the milk. What is the percentage of milk in the mixture?a)80%b)83.33%c)75%d)66.66%Correct answer is 'B'. Can you explain this answer?
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Amilkman professes to sell milk at its CP only. But still he is making a profit of 20% since he has mixed some amount of water in the milk. What is the percentage of milk in the mixture?a)80%b)83.33%c)75%d)66.66%Correct answer is 'B'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Amilkman professes to sell milk at its CP only. But still he is making a profit of 20% since he has mixed some amount of water in the milk. What is the percentage of milk in the mixture?a)80%b)83.33%c)75%d)66.66%Correct answer is 'B'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Amilkman professes to sell milk at its CP only. But still he is making a profit of 20% since he has mixed some amount of water in the milk. What is the percentage of milk in the mixture?a)80%b)83.33%c)75%d)66.66%Correct answer is 'B'. Can you explain this answer?.
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