NEET Exam > NEET Questions > Velocity of sound waves in air is330 m/s.For ...
Start Learning for Free
Velocity of sound waves in air is 330 m/s. For a particular sound in air a path difference of 40 cm is equivalent to phase difference of 1.6π. The frequency of the wave is
- a)165 Hz
- b)150 Hz
- c)660 Hz
- d)330 Hz
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Velocity of sound waves in air is330 m/s.For a particular soundin air ...
Option C 660Hz is correct answer... pi=2×
π×mu/velocity × X 1.6π=2×π×mu/330×0.4. (40 cm convert to m) calculate this u get the answer. So mu i.e,frequency of wave=660 Hz.
Free Test
FREE
| Start Free Test |
Community Answer
Velocity of sound waves in air is330 m/s.For a particular soundin air ...
Understanding the Problem
To find the frequency of the sound wave, we can use the relationship between path difference, phase difference, and frequency.
Key Information Provided
- Velocity of sound in air (v) = 330 m/s
- Path difference (d) = 40 cm = 0.4 m
- Phase difference (Δϕ) = 1.6π radians
Relationship Between Phase Difference and Path Difference
The relationship between path difference and phase difference is given by the formula:
Δϕ = (2π/λ) * d
Where λ is the wavelength.
Finding Wavelength
From the given phase difference and path difference:
1. Rearranging the formula gives us:
λ = (2π * d) / Δϕ
2. Substituting the values:
λ = (2π * 0.4) / (1.6π)
3. Simplifying this:
λ = 0.4 * (2 / 1.6) = 0.5 m
Calculating Frequency
Now, we can find the frequency (f) using the formula:
f = v / λ
1. Substituting the known values:
f = 330 m/s / 0.5 m
2. This gives us:
f = 660 Hz
Conclusion
Thus, the frequency of the sound wave is:
Correct Answer: c) 660 Hz
To find the frequency of the sound wave, we can use the relationship between path difference, phase difference, and frequency.
Key Information Provided
- Velocity of sound in air (v) = 330 m/s
- Path difference (d) = 40 cm = 0.4 m
- Phase difference (Δϕ) = 1.6π radians
Relationship Between Phase Difference and Path Difference
The relationship between path difference and phase difference is given by the formula:
Δϕ = (2π/λ) * d
Where λ is the wavelength.
Finding Wavelength
From the given phase difference and path difference:
1. Rearranging the formula gives us:
λ = (2π * d) / Δϕ
2. Substituting the values:
λ = (2π * 0.4) / (1.6π)
3. Simplifying this:
λ = 0.4 * (2 / 1.6) = 0.5 m
Calculating Frequency
Now, we can find the frequency (f) using the formula:
f = v / λ
1. Substituting the known values:
f = 330 m/s / 0.5 m
2. This gives us:
f = 660 Hz
Conclusion
Thus, the frequency of the sound wave is:
Correct Answer: c) 660 Hz
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?
Question Description
Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?.
Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup